無法導入Python模塊

Question

我創建了以下名為resource.py的Python 3模塊，其中包含兩個函數Read_Cursor和Write_Cursor。 導入模塊時，會出現錯誤，具體取決於導入模塊的方式。

我努力了：

import resource
from resource import *
Read_Cursor=resource.Read_Cursor

resource.py：

def Write_Cursor(Cursor):
        with open("/run/thermostat/Cursor","w") as f: # Set the Cursor position

def Read_Cursor():
        with open("/run/thermostat/Cursor","r") as f:   # Get the Cursor position
                C = int(f.read())
        return C

錯誤：

Traceback (most recent call last):
  File "./index.py", line 6, in <module>
    import resource
  File "/usr/lib/cgi-bin/resource.py", line 5
    def Read_Cursor():
    ^
IndentationError: expected an indented block

Answer 1

錯誤實際上在前一行： with open("/run/thermostat/Cursor","w") as f: # Set the Cursor position ： with語句不完整（檢查[Python 3.Docs]：復合語句-並附上聲明 ）。
要更正它，請執行以下操作：

def Write_Cursor(Cursor):
    with open("/run/thermostat/Cursor","w") as f: # Set the Cursor position
        f.write(str(Cursor))  # Just an example, I don't know how Cursor should be serialized

另外，正如其他人指出的那樣，您應該使用4個 SPACE進行縮進（如[Python]中的建議：PEP 8-Python代碼樣式指南-縮進 ）：

每個縮進級別使用4個空格。

Answer 2

您有不正確的縮進塊，在Python中是4個空格或1個列表

更正的代碼：

def Write_Cursor(Cursor):
    with open("/run/thermostat/Cursor","w") as f: # Set the Cursor position

def Read_Cursor():
    with open("/run/thermostat/Cursor","r") as f:   # Get the Cursor position
        C = int(f.read())
    return C