如何將多個對象依次推入一個對象

Question

我在一個變量中有2個或多個對象，我想將這些對象推入一個對象。

let a = {"device_type":"iphone","filter_data":{"title":{"value":"Lorem Ipsum..","data":{}},"message":{"value":"Lorem Ipsum is simply dummy text of the printing...","data":{}},"dismiss_button":{"value":"Ok","data":{}},"action_url":{"value":"","data":{"type":"custom"}}}}

{"device_type":"iphone","filter_data":{"message":{"value":"Push Message goes here.","data":{}}}}

我希望輸出為：

{
  "0": {
    "device_type": "iphone",
    "filter_data": {
      "title": {
        "value": "Lorem Ipsum..",
        "data": {}
      },
      "message": {
        "value": "Lorem Ipsum is simply dummy text of the printing...",
        "data": {}
      },
      "dismiss_button": {
        "value": "Ok",
        "data": {}
      },
      "action_url": {
        "value": "",
        "data": {
          "type": "custom"
        }
      }
    }
  },
  "1": {
    "device_type": "iphone",
    "filter_data": {
      "message": {
        "value": "Push Message goes here.",
        "data": {}
      }
    }
  }
}

我怎樣才能做到這一點？

Answer 1

您可以將}{替換為},{ ，對其進行解析，並采用Object.assign從數組中獲取具有索引作為屬性的對象。

 const data = '{"device_type":"iphone","filter_data":{"title":{"value":"Lorem Ipsum..","data":{}},"message":{"value":"Lorem Ipsum is simply dummy text of the printing...","data":{}},"dismiss_button":{"value":"Ok","data":{}},"action_url":{"value":"","data":{"type":"custom"}}}}{"device_type":"iphone","filter_data":{"message":{"value":"Push Message goes here.","data":{}}}}'; result = Object.assign({}, JSON.parse(`[${data.replace(/\\}\\{/g, '},{')}]`)); console.log(result); 

 .as-console-wrapper { max-height: 100% !important; top: auto; } 

Answer 2

如果它們在數組中，則非常簡單-只需使用reduce ：

 const data = [{"device_type":"iphone","filter_data":{"title":{"value":"Lorem Ipsum..","data":{}},"message":{"value":"Lorem Ipsum is simply dummy text of the printing...","data":{}},"dismiss_button":{"value":"Ok","data":{}},"action_url":{"value":"","data":{"type":"custom"}}}},{"device_type":"iphone","filter_data":{"message":{"value":"Push Message goes here.","data":{}}}}]; const res = data.reduce((a, c, i) => (a[i] = c, a), {}); console.log(res); 

 .as-console-wrapper { max-height: 100% !important; top: auto; } 

Answer 3

您可以使用Array.protoype.match分隔每個對象，然后使用Array.protoype.reduce獲得預期的對象。

 let a = '{"device_type":"iphone","filter_data":{"title":{"value":"Lorem Ipsum..","data":{}},"message":{"value":"Lorem Ipsum is simply dummy text of the printing...","data":{}},"dismiss_button":{"value":"Ok","data":{}},"action_url":{"value":"","data":{"type":"custom"}}}}{"device_type":"iphone","filter_data":{"message":{"value":"Push Message goes here.","data":{}}}}'; let objects = a.match(/({"device_type".*?}}}})/g).map(e => JSON.parse(e)); console.log('Array of objects',objects) const out = {...[objects]}; console.log('\\ndesired output',out) 

同樣，當鍵只是索引時，將數組轉換為對象似乎沒有用。