[英]Django: Combining two for loops
有沒有辦法將兩個for循環合並為一個? 我一直在尋找這樣的解決方案。 但這不是這樣的:
ticket_stats_by_event = {
x['pk']: {'sold_tickets': x['sold_tickets'], 'available_tickets: y['avaiable_tickets']}
for x, y in sold_tickets_by_event, available_tickets_by_event
}
結果將是:
<EventQuerySet [{'pk': 6, 'organizer': 1, 'available_tickets': 20, 'sold_tickets': 2}, {'pk': 1, 'organizer': 1, 'available_tickets': 1765746, 'sold_tickets': 2116}, {'pk': 5, 'organizer': 1, 'available_tickets': 10, 'sold_tickets': 1}, {'pk': 4, 'organizer': 1, 'available_tickets': 60, 'sold_tickets': 4}]>
這里的全部功能:
def ticket_stats_by_event(self, organizer):
sold_tickets_by_event = [
x for x in self.sold_tickets if x['organizer'] == organizer.pk
]
# <EventQuerySet [{'pk': 6, 'organizer': 1, 'sold_tickets': 1}, {'pk': 1, 'organizer': 1, 'sold_tickets': 529}, {'pk': 5, 'organizer': 1, 'sold_tickets': 1}, {'pk': 4, 'organizer': 1, 'sold_tickets': 2}]>
available_tickets_by_event = [
x for x in self.available_tickets if x['organizer'] == organizer.pk
]
# <EventQuerySet [{'pk': 1, 'organizer': 1, 'available_tickets': 1721}, {'pk': 4, 'organizer': 1, 'available_tickets': 30}, {'pk': 5, 'organizer': 1, 'available_tickets': 10}, {'pk': 6, 'organizer': 1, 'available_tickets': 20}]>
ticket_stats_by_event = {
x['pk']: {'sold_tickets': x['sold_tickets']}
for x in sold_tickets_by_event
}
for item in available_tickets_by_event:
pk = item.pop('pk')
ticket_stats_by_event[pk].update(item)
return ticket_stats_by_event
您可以只使用一個循環而不是四個來編寫這樣的函數:
def ticket_stats_by_event(self, organizer):
ticket_stats_by_event = {}
for st, at in zip(self.sold_tickets, self.available_tickets):
# if organizer is not same in any then skip
if organizer.pk != st['organizer'] or organizer.pk != at['organizer']:
continue
st_pk = st['pk']
st_value = {'sold_tickets': st['sold_tickets'], 'organizer': st['organizer']}
at_pk = at['pk']
at_value = {'available_tickets': at['available_tickets'], 'organizer': at['organizer']}
# add values from sold_tickets_by_event
if st_pk in ticket_stats_by_event:
ticket_stats_by_event[st_pk].update(st_value)
else:
ticket_stats_by_event[st_pk] = st_value
# add values from available_tickets_by_event
if at_pk in ticket_stats_by_event:
ticket_stats_by_event[at_pk].update(at_value)
else:
ticket_stats_by_event[at_pk] = at_value
return ticket_stats_by_event
此外,您可以將其分為三個循環,在第一和第二個循環中,您將獲取特定組織的已售票和可用票。 我沒有使用一種內襯函數來使其更具可讀性。
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