如何在Java中比較兩個ArrayList

Question

我正在制作樂透程序。

我怎么知道一個ArrayList是否包含來自另一個ArrayList的所有數字？

我嘗試的方式。

ArrayList<String> newNumbers = new ArrayList<>();//Define Lotto Scope
ArrayList<String> resultNumbers = new ArrayList<>(); //Only 6 numbers 
ArrayList<String> includingNumbers= new ArrayList<>(); //Number to Include

 public void applyStaticNumbers(){

   for (int i = 1; i < 46; i++) {
        newNumbers.add("" + i);
    }

   Collections.shuffle(newNumbers);

    for (int i = 0; i < 6; i++) {
        resultNumbers.add(newNumbers.get(i));
    }

   resultNumbers.sort(Comparator.comparing(Double::parseDouble)); //sort Numbers

   if (resultNumbers.contains(includingNumbers.get(0))) {
        for (int i = 0; i < 6; i++) {
            textViews.get(i).setText(resultNumbers.get(i));
        }
    } else {//If not included, restart.
        newNumbers.clear();
        resultNumbers.clear();
        applyStaticNumbers();
    }


}

Answer 1

您可以使用containsAll方法

includingNumbers.containsAll(resultNumbers)

Answer 2

您可以使用removeall方法

集合listOne = new ArrayList（Arrays.asList（“ x”，“ y”，“ z”，“ a”，“ b”，“ c”，“ d”）））； 集合listTwo = new ArrayList（Arrays.asList（“ a”，“ b”，“ d”，“ e”，“ f”，“ x”，“ y”）））；

    List<String> sourceList = new ArrayList<String>(listOne);
    List<String> destinationList = new ArrayList<String>(listTwo);


    sourceList.removeAll( listTwo );
    destinationList.removeAll( listOne );