如何比較表的多列和多行

Question

我有一個大數據表，看起來像這樣

ID    Marker    Value1    Value2
================================
1     A         10        11
1     B         12        13
1     C         14        15
2     A         10        11
2     B         13        12
2     C
3     A         10        11
3     C         12        13

我想通過以下數據搜索此數據，這些數據是用戶輸入的而不是存儲在表中：

Marker    Value1    Value2
==========================
A         10        11
B         12        13
C         14        14

結果應該是這樣的：

ID    Marker    Value1    Value2    Match?
==========================================
1     A         10        11        true
1     B         12        13        true
1     C         14        15        false
2     A         10        11        true
2     B         13        12        true
2     C                             false  
3     A         10        11        true
3     C         12        13        false

最終，這是必要的（上表不是必需的，它應該證明這些值是如何產生的）：

ID    Matches    Percent
========================
1     2          66%
2     2          66%
3     1          33%

我正在尋找最有前途的方法來使其在SQL（確切地說是PostgreSQL）中起作用。

我的想法：

1. 創建一個臨時表，將其與上述表連接並將結果分組
2. 使用CASE WHEN或臨時過程僅使用一個（可能是（腫的）查詢

我對這兩種方法都不滿意，因此提出了問題。 如何有效地比較兩個這樣的表？

Answer 1

您可以使用CTE預先計算匹配項。 然后，簡單的聚合即可解決問題。 假設您的參數是：

Marker    Value1    Value2
==========================
m1        x1        y1
m2        x2        y2
m3        x3        y3

你可以做：

with x as (
  select
    id,
    case when 
       marker = :m1 and (value1 = :x1 and value2 = :y1 or value1 = :y1 and value2 = :x1)
    or marker = :m2 and (value1 = :x2 and value2 = :y2 or value1 = :y2 and value2 = :x2)
    or marker = :m3 and (value1 = :x3 and value2 = :y3 or value1 = :y3 and value2 = :x3)
    then 1 else 0 end as matches
  from t
)
select
  id,
  sum(matches) as matches,
  100.0 * sum(matches) / count(*) as percent
from x
group by id

Answer 2

嘗試這個：

CREATE TABLE #Temp
(
    Marker nvarchar(50),
    Value1 nvarchar(50),
    Value2 nvarchar(50)
)

INSERT INTO #Temp Values ('A', '10', '11')
INSERT INTO #Temp Values ('B', '12', '13')
INSERT INTO #Temp Values ('C', '14', '14')


SELECT m.Id, m.Marker, m.Value1, m.Value2, 
  (Select 
    CASE
        WHEN COUNT(*) = 0 THEN 'False'
        WHEN COUNT(*) <> 0 THEN 'True'
    END
    FROM #Temp t 
    WHERE t.Marker = m.Marker and t.Value1 = m.Value1 and t.Value2 = m.Value2) as Matches

FROM [Test].[dbo].[Markers] m
ORDER BY Matches DESC

Drop TABLE #Temp

如果這正是您想要的，我會嘗試解決它的第二部分。

Answer 3

可以使用公用表表達式中的VALUES子句提供用戶輸入，然后可以在與實際表的左聯接中使用該用戶輸入。

with user_input (marker, value1, value2) as (
  values 
    ('A', 10, 11),
    ('B', 12, 13),
    ('C', 14, 14)
)
select d.id,
       count(*) filter (where (d.marker, d.value1, d.value2) is not distinct from (u.marker, u.value1, u.value2)), 
       100 * count(*) filter (where (d.marker, d.value1, d.value2) is not distinct from (u.marker, u.value1, u.value2)) / cast(count(*) as numeric) as pct
from data d
  left join user_input u on (d.marker, d.value1, d.value2) = (u.marker, u.value1, u.value2)
group by d.id
order by d.id;  

返回：

id | count | pct  
---+-------+------
 1 |     2 | 66.67
 2 |     2 | 66.67
 3 |     1 | 50.00

在線示例： https ： //rextester.com/OBOOD9042

編輯

如果值的順序無關緊要（因此（12,13）被認為與（13,12）相同），則比較會變得更加復雜。

with user_input (marker, value1, value2) as (
  values 
    ('A', 10, 11),
    ('B', 12, 13),
    ('C', 14, 14)
)
select d.id,
       count(*) filter (where (d.marker, least(d.value1, d.value2), greatest(d.value1, d.value2)) is not distinct from (u.marker, least(u.value1, u.value2), greatest(u.value1, u.value2)))
from data d
  left join user_input u on (d.marker, least(d.value1, d.value2), greatest(d.value1, d.value2)) = (u.marker, least(u.value1, u.value2), greatest(u.value1, u.value2))
group by d.id
order by d.id;