如何使用匹配變量名稱的字符串訪問和賦值給變量

Question

我想通過使用字符串equals到變量名來定位類中的變量（屬性）。 有辦法嗎？

class Person {

  let name: String
  let email: String
  let address: String

  let propertiesMap: [String : String] = [
    "person_name": "name",
    "person_email_address": "email"
  ]

  init(_ data: NSDictionary) {

     for element in data {
       # string key address of Person property 
         propertiesMap[ element.key ]

       # value to be assigned to the property 
         element.value

     }
  }  
}

我希望循環遍歷數據NSDictionary，如果字典的鍵匹配類的屬性，則將數據NSDictionary中的鍵值賦給class屬性

Answer 1

一種方式可能是

class Person: NSObject{
    @objc var name: String?
    @objc var email: String?


    class func from(dict: [String:String]) -> Person{
        let v = Person()
        for element in dict{
            v.setValue(element.value, forKey: element.key)
        }
        return v
    }
}


func test(){
    let p = Person.from(dict: ["name":"John","email":"john@doe.com"])
    print("name \(p.name ?? ""), email \(p.email ?? "")")
}