[英]Ansible regex tomcat version
我現在正在為一個問題苦苦掙扎幾個小時,我想在task文件中僅對特定版本的tomcat做一個動作,例如:
- name: Copy new context.xml(Manager App) for tomcat8 or 9
template:
src: templates/tomcat8-9/manager/context.xml
dest: /usr/share/tomcat/webapps/manager/META-INF/context.xml
owner: tomcat
group: tomcat
when: "{{ tomcat_ver }}" is match("^[8-9]")
如果我的tomcat_ver是9.0.20,則它應該與模式匹配,但是出現一個奇怪的錯誤,我看不到我缺少任何報價的地方
fatal: [tomcatbis]: FAILED! => {"reason": "Syntax Error while loading YAML.\n did not find expected key\n\nThe error appears to be in '/projects/ansibles/roles/tomcat/tasks/tomcat-setup-Debian.yml': line 69, column 28, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n group: tomcat\n when: \"{{ tomcat_ver }}\" is match(\"^[8-9]\")\n ^ here\nWe could be wrong, but this one looks like it might be an issue with\nmissing quotes. Always quote template expression brackets when they\nstart a value. For instance:\n\n with_items:\n - {{ foo }}\n\nShould be written as:\n\n with_items:\n - \"{{ foo }}\"\n"}
謝謝你的幫助。
它應該像下面這樣:
---
- hosts: localhost
tasks:
- name: plat
debug:
msg: "Success"
when: '"{{ tomcat_ver }}" is match("^[8-9]")'
開頭和結尾的單引號
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