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[英]Python: Slice list into sublists, every time element begins with specific substring
[英]Split list into sublists at every occurrence of element starting with specific substring
我有一個包含一串字符串的大列表。 我需要將原始列表的元素排序到一個嵌套列表中,這取決於它們在列表中的位置。 換句話說,我需要將原始列表分解為子列表,其中每個子列表包含所有以'ABC'開頭的元素之間的所有元素,然后將它們作為嵌套列表連接在一起。
因此,原始列表為:
all_results = ['ABCAccount', 'def = 0', 'gg = 0', 'kec = 0', 'tend = 1234567890', 'ert = abc', 'sed = target', 'id = sadfefsd3g3g24b24b', 'ABCAccount', 'def = 0', 'gg = 0', 'kec = 0', 'tend = NA', 'ert = abc', 'sed = source', 'id = sadfefsd3g3g24b24b', 'ABCAdditional', 'addkey = weds', 'addvalue = false', 'ert = abc', 'sed = target', 'id = sadfefsd3g3g24b24b', 'time_zone = EDT’]
我需要退貨:
split_results = [['ABCAccount','def = 0', 'gg = 0', 'kec = 0', 'tend = 1234567890', 'ert = abc', 'sed = target', 'id = sadfefsd3g3g24b24b'],['ABCAccount', 'def = 0', 'gg = 0', 'kec = 0', 'tend = NA', 'ert = abc', 'sed = source', 'id = sadfefsd3g3g24b24b'],['ABCAdditional', 'addkey = weds', 'addvalue = false', 'ert = abc', 'sed = target', 'id = sadfefsd3g3g24b24b', 'time_zone = EDT’]]
我嘗試了以下方法:
split_results = [l.split(',') for l in ','.join(all_results).split('ABC')]
您可以直接從原始列表中進行工作:
def make_split( lst ):
if len(lst) == 0:
return []
r0 = []
r1 = []
for s in lst:
if s.startswith("ABC"):
if r1:
r0.append(r1)
r1 = []
r1.append(s)
return r0 + [r1]
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