![](/img/trans.png)
[英]In python,how to output all the files name with the same extension in a directory?
[英]Search all files with same name in a directory python
我有一個問題:我需要獲取目錄中文件的路徑,我有一個包含其他文件夾和其他文件夾等的文件夾。。。每個文件夾都包含一個文件“ tv.sas7bdat”,我需要獲取每個文件該文件的路徑。 謝謝 !!!
您可以嘗試以下代碼,其中PATH代表父目錄
import os
def getAlldirInDiGui(path,resultList):
filesList=os.listdir(path)
for fileName in filesList:
fileAbpath=os.path.join(path,fileName)
if os.path.isdir(fileAbpath):
getAlldirInDiGui(fileAbpath,resultList)
else:
if fileName=='tv.sas7bdat':
resultList.append(fileAbpath)
resultList = []
PATH = ""
getAlldirInDiGui(PATH,resultList)
希望下面的代碼完全可以為您工作:
import glob
initial_path = "c:\<intital folder location>"
files = [file for file in glob.glob(initial_path+ "tv.sas7bdat" , recursive=True)]
for f in files:
print(f)
您可以結合使用os
python軟件包和遞歸函數來搜索特定目錄
import os
from os.path import isfile, join, isdir
def get_files_path(directory, paths):
for item in os.listdir(directory):
if isfile(join(directory, item)) and item == "tv.sas7bda":
paths.append(directory + item)
elif isdir(directory+item):
get_files_path(directory + item, paths)
return paths
directory_to_search = "./"
get_files_path(directory_to_search , [])
您可以使用os.walk()
import os
for root, dirs, files in os.walk(os.getcwd()):
for f in files:
if f.find("tv.sas7bdat")>=0:
print(root,f)
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.