![](/img/trans.png)
[英]JSON Objects in Swift 5 using Swift JSON, how can i make a JSON object like this :
[英]how to write json objects one by one in to a json object in swift
我需要使用嵌套對象創建答案JSON
我嘗試使用mappable,但無法解決問題
我需要創建這種數組
{
"interactionId":"daade6b6adcd8b063a355e28bc1f1341",
"futureSurveyAnswers":[
{
"type":"imagepicker",
"qcode":"vxo20zeezo",
"values":[
{
"value":"lion"
}
]
},
{
"type":"radiogroup",
"qcode":"s4ep4s0shf",
"values":[
{
"value":"item1"
}
]
},
{
"type":"checkbox",
"qcode":"76k5cpnpki",
"values":[
{
"value":"item1"
},
{
"value":"item2"
}
]
}
],
"originalResultArray":"{\"question2\":\"item1\",\"question3\":[\"item1\",\"item2\"],\"question1\":\"lion\"}"
}
當前,最好使用的最佳解決方案是Codable
協議。 在線上有很多示例和教程,因此請檢查一兩個,我相信您會發現它非常易於使用。
關鍵是您可以直接在JSON上編碼具體的類或結構。 因此,您的問題就不在JSON本身,而只是結構化您的類。 例如:
class Survey {
class Answer {
enum AnswerType: String {
case imagepicker
}
class Value {
var value: String?
}
var type: AnswerType = .imagepicker
var qcode: String?
var values: [Value] = [Value]()
}
let interactionId: String
var futureSurveyAnswers: [Answer] = [Answer]()
var originalResultArray: String?
init(interactionId: String) { self.interactionId = interactionId }
}
這樣,您可以輕松地根據需要修改結構。 例如:
let survey = Survey(interactionId: "0")
survey.futureSurveyAnswers.append({
let answer = Survey.Answer()
answer.qcode = "test"
return answer
}())
因此,要將其擴展到可編碼,您實際上需要將可Codable
協議附加到您的類和任何嵌入式組件中:
class Survey: Codable {
class Answer: Codable {
enum AnswerType: String, Codable {
case imagepicker
}
class Value: Codable {
var value: String?
}
var type: AnswerType = .imagepicker
var qcode: String?
var values: [Value] = [Value]()
}
let interactionId: String
var futureSurveyAnswers: [Answer] = [Answer]()
var originalResultArray: String?
init(interactionId: String) { self.interactionId = interactionId }
}
現在,您可以像以下這樣簡單地獲取JSON:
let survey = Survey(interactionId: "0")
survey.futureSurveyAnswers.append({
let answer = Survey.Answer()
answer.values.append({
let value = Survey.Answer.Value()
value.value = "some"
return value
}())
answer.qcode = "test"
return answer
}())
let encoder = JSONEncoder()
if let jsonData = try? encoder.encode(survey) {
print("Generated data: \(jsonData)")
}
我希望這能為您指明正確的方向。
從注釋中可以看出,這是我用作JSON的測試示例:
class Survey: Codable {
class Answer: Codable {
enum AnswerType: String, Codable {
case imagepicker
}
class Value: Codable {
var value: String?
init(value: String? = nil) { self.value = value }
}
var type: AnswerType = .imagepicker
var qcode: String?
var values: [Value] = [Value]()
}
let interactionId: String
var futureSurveyAnswers: [Answer] = [Answer]()
var originalResultArray: String?
init(interactionId: String) { self.interactionId = interactionId }
}
func addTestAnswer(to survey: Survey) {
let answer = Survey.Answer()
answer.values.append(.init(value: "Random value \(Int.random(in: 1...100))"))
answer.values.append(.init(value: "Random value \(Int.random(in: 1...100))"))
answer.values.append(.init(value: "Random value \(Int.random(in: 1...100))"))
answer.values.append(.init(value: "Random value \(Int.random(in: 1...100))"))
survey.futureSurveyAnswers.append(answer)
}
func testRandomSurveyJSON() {
let survey = Survey(interactionId: "randomSurvey")
addTestAnswer(to: survey)
addTestAnswer(to: survey)
addTestAnswer(to: survey)
addTestAnswer(to: survey)
addTestAnswer(to: survey)
print("Got JSON: \(String(data: try! JSONEncoder().encode(survey), encoding: .utf8)!)")
}
並得到以下結果:
Got JSON: {"interactionId":"randomSurvey","futureSurveyAnswers":[{"type":"imagepicker","values":[{"value":"Random value 74"},{"value":"Random value 4"},{"value":"Random value 26"},{"value":"Random value 93"}]},{"type":"imagepicker","values":[{"value":"Random value 43"},{"value":"Random value 65"},{"value":"Random value 38"},{"value":"Random value 88"}]},{"type":"imagepicker","values":[{"value":"Random value 56"},{"value":"Random value 88"},{"value":"Random value 57"},{"value":"Random value 94"}]},{"type":"imagepicker","values":[{"value":"Random value 66"},{"value":"Random value 52"},{"value":"Random value 89"},{"value":"Random value 27"}]},{"type":"imagepicker","values":[{"value":"Random value 53"},{"value":"Random value 93"},{"value":"Random value 30"},{"value":"Random value 55"}]}]}
這似乎是正確的。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.