簡體   English   中英

重用相關子查詢的結果

[英]Reuse result of a correlated subquery

我有一個表media_tags其中包含將媒體鏈接到用戶定義的標簽的兩列。 我想進行一些查詢,以選擇標簽上條件復雜的媒體。 我當前的解決方案是多次使用相同的相關子查詢。

多個SO答案已將我引向CTE,但據我所知,它們只能用於替換不相關的子查詢。

SELECT outer.media_id
FROM media_tags AS outer
WHERE 1 IN (SELECT tag_id FROM media_tags AS inner WHERE outer.media_id = inner.media_id)
AND 2 NOT IN (SELECT tag_id FROM media_tags AS inner WHERE outer.media_id = inner.media_id)
AND (3 IN (SELECT tag_id FROM media_tags AS inner WHERE outer.media_id = inner.media_id)
OR 4 IN (SELECT tag_id FROM media_tags AS inner WHERE outer.media_id = inner.media_id));

使用not exists怎么樣?

SELECT m2.media_id
FROM media_tags mt
WHERE NOT EXISTS (SELECT tag_id
                  FROM media_tags mt2
                  WHERE mt2.media_id = mt.media_id AND
                        mt2.tag_id IN (1, 2, 3, 4)
                 );

您可以使用GROUP BY media_id進行自我連接,並在HAVING子句中設置條件:

SELECT outer.media_id
FROM media_tags AS outer INNER JOIN media_tags AS inner
ON outer.media_id = inner.media_id
GROUP BY outer.media_id
HAVING 
  SUM(inner.tag_id = 1) > 0
  AND
  SUM(inner.tag_id = 2) = 0
  AND
  SUM(inner.tag_id IN (3, 4)) > 0

如果沒有自連接,甚至更簡單,請檢查是否也可以:

SELECT media_id
FROM media_tags
GROUP BY media_id
HAVING 
  SUM(tag_id = 1) > 0
  AND
  SUM(tag_id = 2) = 0
  AND
  SUM(tag_id IN (3, 4)) > 0

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM