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在使用group_by之后,如何對數據幀(sample_n)進行隨機采樣並計算匯總統計信息,並迭代999次?

[英]How to randomly sample dataframe (sample_n) and calculate summary statistics after using group_by, and iterate 999 times?

在基於兩個分類因素(plant_sp =植物種類和地點)對數據進行分組之后,我想對數據幀(test_df)進行重新采樣並計算數值響應變量(sp_rich)的摘要統計量(均值和標准差)。 然后,我希望此過程可以重復進行999次。 另外,我想使用多個樣本大小對數據幀進行重新采樣,並計算以上統計信息並執行迭代。

歸根結底,我真的很想將它放在dplyr / tidy框架中,因為我對這種樣式更加熟悉,但是可以接受基本的R /其他選項。

因此,這是一個示例數據幀:

test_df <- structure(list(plant_sp = c("plant_1", "plant_1", "plant_1", "plant_1", "plant_1",
                                       "plant_1", "plant_1", "plant_1", "plant_1", "plant_1", 
                                       "plant_2", "plant_2", "plant_2", "plant_2", "plant_2",
                                       "plant_2", "plant_2", "plant_2", "plant_2", "plant_2"), 
                          site = c("a", "a", "a", "a", "a",  
                                   "b", "b", "b", "b", "b",  
                                   "a", "a", "a", "a", "a",
                                   "b", "b", "b", "b", "b"),
                          sp_rich = c(5, 3, 5, 3, 5, 
                                      7, 8, 8, 8, 10,
                                      1, 4, 5, 6, 3, 
                                      7, 3, 12, 12,11)), 
                     row.names = c(NA, -20L), class = "data.frame", 
                     .Names = c("plant_sp", "site", "sp_rich"))
# I can calculate the summary statistics for one iteration,   
# and for one sample size at a time:

mean_calc <- test_df %>%
  group_by(plant_sp, site) %>%
  do(sample_n(., 3)) %>%
  summarise(mean = mean(sp_rich),
            sd = sd((sp_rich))) %>%
  mutate(sample_size = n())

> mean_calc
# A tibble: 4 x 5
# Groups:   plant_sp [2]
  plant_sp site   mean    sd sample_size
  <fct>    <fct> <dbl> <dbl>       <dbl>
1 A        GHT    7    2               3
2 A        PE     3.33 0.577           3
3 B        GHT    3.33 1.53            3
4 B        PE     1.67 0.577           3
# I can also manually perform the calculations manually for   
# each sample size, and put the data together (hack):

# Do this manually for two different samples sizes
mean_calc_3 <- test_df %>%
  group_by(plant_sp, site) %>%
  do(sample_n(., 3)) %>%
  summarise(mean = mean(sp_rich),
            sd = sd((sp_rich))) %>%
  mutate(sample_size = 3)
mean_calc_3

mean_calc_4 <- test_df %>%
  group_by(plant_sp, site) %>%
  do(sample_n(., 4)) %>%
  summarise(mean = mean(sp_rich),
            sd = sd((sp_rich))) %>%
  mutate(sample_size = 4)
mean_calc_4

mean_calc <- bind_rows(mean_calc_3, mean_calc_4) 
mean_calc <- mean_calc %>%
    group_by(plant_sp, site, sample_size) %>%
    arrange(sample_size, plant_sp, site)

# A tibble: 8 x 5
# Groups:   plant_sp, site, sample_size [8]
  plant_sp site   mean    sd sample_size
  <fct>    <fct> <dbl> <dbl>       <dbl>
1 A        GHT    5.67  1.53           3
2 A        PE     4.33  1.53           3
3 B        GHT    3.67  1.15           3
4 B        PE     2     1              3
5 A        GHT    6.5   2.08           4
6 A        PE     4.25  1.26           4
7 B        GHT    2.75  0.5            4
8 B        PE     2.25  0.5            4

我真的很想自動執行跨多個樣本大小的這些計算(例如,n = 3,n = 4,在此示例中,適當的數據將具有〜5-10個不同大小的類別),然后將整個過程進行999次迭代。

mean_calc df的結構最終是我要尋找的輸出,而不是一次計算平均值和sd,匯總統計量被計算999次並取平均值。

library(tidyverse) 
...<your test_df>...

test_df %>% group_by(plant_sp, site) %>% 
            nest() %>% 
            crossing(sample_size=c(3,4,5), iter = seq(1:10)) %>% 
            mutate(sample_data = map2(data, sample_size, ~sample_n(.x,.y))) %>% 
            mutate(calc = map(sample_data, 
                    ~summarise(.,mean = mean(sp_rich),sd = sd((sp_rich))))) %>% 
            select(plant_sp, site, sample_size, iter, calc) %>% 
            unnest() %>% 
            group_by(plant_sp, site, sample_size) %>%
            arrange(sample_size, plant_sp, site)

此處的樣本大小為c(3,4,5) ,迭代為10

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