[英]Vector iterator type unknown
我正在學習 C++,這是我第一次使用迭代器
我已經寫下了這段代碼:
std::pair<max, max> ConvertToAStarMap::GetLimits(std::string map)
{
// Init max and min variables.
int max_x = std::numeric_limits<int>::min();
int min_x = std::numeric_limits<int>::max();
int max_y = max_x;
int min_y = min_x;
std::vector<std::string> map_cells = ConvertToAStarMap::split(map, ';');
for (std::string::iterator it = map_cells.begin(); it != map_cells.end(); ++it)
}
我得到這個錯誤:
ConvertToAStarMap.cpp: In member function ‘std::pair<max, max> ConvertToAStarMap::GetLimits(std::__cxx11::string)’:
ConvertToAStarMap.cpp:31:52: error: conversion from ‘std::vector<std::__cxx11::basic_string<char> >::iterator {aka __gnu_cxx::__normal_iterator<std::__cxx11::basic_string<char>*, std::vector<std::__cxx11::basic_string<char> > >}’ to non-scalar type ‘std::__cxx11::basic_string<char>::iterator {aka __gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char> >}’ requested
for (std::string::iterator it = map_cells.begin(); it != map_cells.end(); ++it)
~~~~~~~~~~~~~~~^~
ConvertToAStarMap.cpp:31:59: error: no match for ‘operator!=’ (operand types are ‘std::__cxx11::basic_string<char>::iterator {aka __gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char> >}’ and ‘std::vector<std::__cxx11::basic_string<char> >::iterator {aka __gnu_cxx::__normal_iterator<std::__cxx11::basic_string<char>*, std::vector<std::__cxx11::basic_string<char> > >}’)
for (std::string::iterator it = map_cells.begin(); it != map_cells.end(); ++it)
~~~^~~~~~~~~~~~~~~~~~
怎么了? 我不明白。
最簡單的做法是:
for (const auto& cell : map_cells)
如果您不想使用基於范圍的 for 循環:
for (auto it = map_cells.begin();......
問題是你想迭代向量,而不是字符串,所以它應該是:
for (std::vector<std::string>::iterator it = map_cells.begin();......
此信息在第 2 點中的錯誤中可用。:
'std::vector<std::__cxx11::basic_string<char> >::iterator
__gnu_cxx::__normal_iterator<std::__cxx11::basic_string<char>*, std::vector<std::__cxx11::basic_string<char> > >
}'std::__cxx11::basic_string<char>::iterator
__gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char> >
}'
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