訪問 json 中的嵌套數組

Question

讓年齡 = 數據 .filter(isDog) .map(dogYears) .reduce(sum);

毫升/小時

我想找到在 javascript 對象中訪問數組元素的最佳方式。 例如：我想找到每門課程的第一個教員名稱和第一個專業。

var students = 
{  
   deptartment:[  
      {  
         name:'Computer Science',
         age:20,
         Course:[  
            {  id: 100000
               name:'Object Oriented Programming',
               faculty:[  
                  {  
                     id:123,
                     name:'John',
                     Specialization: [
                       {name: 'science'},
                       {name: 'Physics'}
                     ]
                  }
                ]
            },
            {  id: 100001
               name:'C#',
               faculty:[    
                 {  
                     id:124,
                     name:'Denis', 
                     Specialization: [
                       {name: 'Ecnonomics'},
                       {name: 'Physics'}
                     ]
                  }
               ]
            }
         ],

      }
    ]
};

我知道我可以通過以下方式獲得教員名稱和專業

  var courses= deptartment && deptartment.Course ;
    var facultyWithSpecialization= {};
    if(courses){
      courses.forEach(course =>{
        var fname = course.faculty && course.faculty[0].name;
        var s= course.faculty && course.faculty.Specialization;
        facultyWithSpecialization[fname] = s && s[0].name;
      })
    }

使用 Object.assign({}, deptartment.Course) 而不是 Department.Course

嘗試使用以下代碼，但沒有太大區別。

 var courses=Object.values(Object.assign({}, deptartment.Course));
var fname = Object.values(Object.assign({}, course.faculty[0].Specialization[0]));

期待

'John': 'science'
'Denis': 'Ecnonomics'

Answer 1

你可以試試這個。 對象中有很多錯誤，包括拼寫錯誤和格式錯誤

 var students = { deptartment: [{ name: 'Computer Science', age: 20, Course: [{ id: 100000, name: 'Object Oriented Programming', faculty: [{ id: 123, name: 'John', Specialization: [{ name: 'science' }, { name: 'Physics' } ] }, { id: 124, name: 'Denis', Specialization: [{ name: 'Ecnonomics' }, { name: 'Physics' } ] } ] }], }] } var obj = {}; students.deptartment.forEach((e) => { e.Course.forEach((k) => { k.faculty.forEach((l) => { obj[l.name] = l.Specialization[0].name }) }) }) console.log(obj)

Answer 2

我覺得你的意思department ，而不是deptartment 。 我修改了你的 JSON，因為它有點問題：

var students = {  
   departments:[  
      {  
         name:'Computer Science',
         age:20,
         Courses:[  
            {  id: 100000,
               name:'Object Oriented Programming',
               faculty:[  
                  {  
                     id:123,
                     name:'John',
                     Specialization: [
                       {name: 'science'},
                       {name: 'Physics'}
                     ]
                  },
                 {  
                     id:124,
                     name:'Denis', 
                     Specialization: [
                       {name: 'Ecnonomics'},
                       {name: 'Physics'}
                     ]
                  }
               ]
            }
         ],
      }]
}

您可以使用map來實現這種嵌套：

students.departments.map(
  department => department.Courses.map(
    course => course.faculty.map(
      student => ({
        name: student.name,
        specialization: student.Specialization[0].name // check nulls here!
      })
    )
  )
)