[英]How to populate a selectbox depending on another selectbox using PHP JSON ARRAY
[英]How do I populate values of an JSON object data into a selectbox?
當使用此代碼選擇框選項值數據填充為 UNDEFINED ..
var obj = jQuery.parseJSON('['+<?= $customers_json; ?>+']') ;
var myJSON = JSON.stringify(obj);
for (var i = 0; i < myJSON.length; i++)
{
html_code += '<option value="'+myJSON[id].toString()+'">'+myJSON.toString()+'</option>';
}
$sql2 = "SELECT id,name FROM customers";
$customerResult = $conn->query($sql2);
//$customers123 = $customerResult->fetch_assoc();
while($r = mysqli_fetch_assoc($customerResult)) {
$rows[] = $r;
}
$customers123=json_encode($rows);
$customers_json = $customers123;
var myJSON = jQuery.parseJSON('['+"[{\\"id\\":\\"2\\",\\"name\\":\\"sooraj\\"},{\\"id\\":\\"4\\",\\"name\\":\\"ravi pillai\\"},{\\"id\\":\\"5\\",\\"name\\":\\"jasil\\"},{\\"id\\":\\"6\\",\\"name\\":\\"athul\\"},{\\"id\\":\\"7\\",\\"name\\":\\"dheeraj123\\"}]"+']') ; myJSON =myJSON[0]; let html_code =''; for (var i = 0; i < myJSON.length; i++) { html_code += '<option value="'+myJSON[i]['id']+'">'+myJSON[i]['name']+'</option>'; } console.log(html_code);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
For 循環將是
for (var i = 0; i < myJSON.length; i++)
{
html_code += '<option value="'+myJSON[i]['id'].toString()+'">'+myJSON[i]['name'].toString()+'</option>';
}
您的解決方案是使用 for 和 in。它是遍歷對象的好方法:
var obj = jQuery.parseJSON('['+<?= $customers_json; ?>+']');
obj = obj[0][0]; // to account for position within object
for (key in obj)
{
html_code += '<option value="'+key+'">'+obj[key]+'</option>';
}
請記住,在添加更多選項之前,您可能需要刪除所有以前的選項:o)
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