[英]Problem with sending data to server with ajax
我已經編寫了一個代碼,可以使用HTML從數據庫中創建一個表,並且希望在每一行上都具有刪除和確認按鈕。 我將整個行放在<form method="post">
屬性中。 在JavaScript文件中,我讀取了電子郵件的值,並使用ajax將其發送到服務器,然后服務器執行該操作。 問題是當我想刪除一行或使用每一行的按鈕確認它時,即使我單擊另一行的按鈕,它也僅適用於第一行。 我使用document.getElementById('email')
但它總是返回第一行。 這是我的html代碼:
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>نام کاربر</th>
<th>ایمیل</th>
<th>تایید</th>
</tr>
</thead>
<tbody>
<?php
while ($users = mysqli_fetch_assoc($result_user)) {
?>
<tr>
<form name="ajax-demo" id="ajax-demo" method="get">
<td><?php echo $users['name']?></td>
<td><?php echo $users['email']?></td>
<input id="email" type="hidden" name="email" value="<?php echo $users['email']?>">
<td>
<div class="btn-group">
<button onclick="confirmUser()" id="btnConfirm" type="submit" class="btn btn-success btn-flat">
تایید
</button>
<button type="button" class="btn btn-success btn-flat dropdown-toggle" data-toggle="dropdown">
<span class="caret"></span>
<span class="sr-only">Toggle Dropdown</span>
</button>
<ul class="dropdown-menu" role="menu">
<li>
<a onclick="deleteUser()" id="btnDelete">حذف</a>
</li>
</ul>
</div>
</td>
</form>
</tr>
<?php }?>
</tbody>
</table>
和javaScript代碼:
<script>
function confirmUser() {
var email = document.getElementById("email").value;
var xhr;
if (window.XMLHttpRequest) { // Mozilla, Safari, ...
xhr = new XMLHttpRequest();
} else if (window.ActiveXObject) { // IE 8 and older
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
var data = "email=" + email;
xhr.open("POST", "confirm_user.php", true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(data);
xhr.onreadystatechange = display_data;
function display_data() {
if (xhr.readyState == 4) {
if (xhr.status == 200) {
//alert(xhr.responseText);
document.getElementById("txtHint").innerHTML = xhr.responseText;
} else {
alert('There was a problem with the request.');
}
}
}
}
function deleteUser() {
var email = document.getElementById("email").value;
var xhr;
if (window.XMLHttpRequest) { // Mozilla, Safari, ...
xhr = new XMLHttpRequest();
} else if (window.ActiveXObject) { // IE 8 and older
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
var data = "email=" + email;
xhr.open("POST", "confirm_user_delete.php", true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(data);
xhr.onreadystatechange = display_data;
function display_data() {
if (xhr.readyState == 4) {
if (xhr.status == 200) {
//alert(xhr.responseText);
document.getElementById("txtHint").innerHTML = xhr.responseText;
} else {
alert('There was a problem with the request.');
}
}
}
}
</script>
最后是我的confirm_user.php代碼:
<?php
$conn = mysqli_connect('localhost', 'root', 'root', 'my_scheme');
if (!$conn) {
die('Connection failed ' . mysqli_error($conn));
}
if (isset($_POST['email'])) {
$email_user = $_POST['email'];
$sql = "UPDATE my_scheme.tbl_user SET active='true' WHERE email='".$email_user."'";
if (mysqli_query($conn, $sql)) {
echo '<h5 class="headline text-green">کاربر با موفقیت تایید شد!</h5>';
}else {
echo "Error: ". mysqli_error($conn);
}
exit();
}
else {
echo "failed";
}
Confirm_user_delete.php代碼類似於之前的代碼。 請幫助我解決此問題。 謝謝
如果我理解您的問題對。 您具有從數據庫結果創建表行的數據庫輸入。 但是,即使您單擊第二個元素,也總是從表行中獲取第一封電子郵件的ID。
原因:您可以像這樣簡單地進行操作
<?php
$email = 'myemail.com';
?>
<button onclick="confirmUser('<?php echo $email; ?>')"class="btn btn-success btn-flat"> Delete Me </button>
<script>
function confirmUser(email)
{
console.log("The email to delete is: " + email);
}
</script>
<button onclick="confirmUser(this)" data-email="<?php echo $users['email']?>" id="btnConfirm" type="submit" class="btn btn-success btn-flat">تایید</button>
並在js函數中:
function confirmUser(this) {
var email = this.getAttribute("email");
var xhr;
if (window.XMLHttpRequest) { // Mozilla, Safari, ...
xhr = new XMLHttpRequest();
} else if (window.ActiveXObject) { // IE 8 and older
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
var data = "email=" + email;
xhr.open("POST", "confirm_user.php", true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(data);
xhr.onreadystatechange = display_data;
function display_data() {
if (xhr.readyState == 4) {
if (xhr.status == 200) {
//alert(xhr.responseText);
document.getElementById("txtHint").innerHTML = xhr.responseText;
} else {
alert('There was a problem with the request.');
}
}
}
}
刪除操作相同。
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