如何從兩個表中獲取數據，第二個表顯示行數

Question

我想顯示申請表中的學位和相關學位ID的數量。

    SELECT * FROM degrees, applications 
where (SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND `campus_id` =$campus 
AND DATE(`created_at`) = CURDATE() )  AS today, 
(SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND `campus_id` =$campus AND DATE(`created_at`) != CURDATE() )  AS previous, 
(SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND finalSubmission = 1 and response_status = 0 and `campus_id` =$campus)  AS pending, 
(SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND response_status = 1 and `campus_id` =$campus )  AS approved, 
(SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND response_status = 2 and `campus_id` =$campus )  AS rejected, 
(SELECT COUNT(*) FROM applications WHERE degree_id = degrees.id AND finalSubmission = 1 and `campus_id` =$campus ) AS Total

Answer 1

選擇DISTINCT degree.id，degrees.title，

(SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND `campus_id` =1 AND DATE(`created_at`) = CURDATE() )  AS today,

    (SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND `campus_id` =1 AND DATE(`created_at`) != CURDATE() )  AS previous,

    (SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND finalSubmission = 1 and response_status = 0 and `campus_id` =1 )  AS pending,

    (SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND response_status = 1 and `campus_id` =1 )  AS approved,

    (SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND response_status = 2 and `campus_id` =1 )  AS rejected,

    (SELECT COUNT(*) FROM applications
    WHERE degree_id = degrees.id AND finalSubmission = 1 and `campus_id` =1 ) AS Total

從度

Answer 2

SELECT DISTINCT degree.id， campus_id ，（從今天的應用程序中選擇COUNT（id） campus_id = Degrees.id AND campus_id = 1 AND DATE（ created_at ）= CURDATE（））截至今天為止，（SELECT COUNT（ ）從應用程序中where degree_id = campus_id AND campus_id = 1 AND DATE（ created_at ！！= CURDATE（））如先前，（ 從COUNT_id = Degrees.id AND finalSubmission = 1且response_status = 0和campus_id = 1的應用程序中選擇COUNT（ ），如待處理， （已從度為id_id = Degrees.id AND response_status = 1且campus_id = 1的應用程序中選擇COUNT（ ）通過了AS的批准； 從度為度數id = degree.id和response_status = 2的應用程序中為 SELECT COUNT（= 1的應用程序中，並且campus_id = 1）被拒絕的AS， （從應用程序SELECT COUNT（ ），其中degree_id = campus_id和finalSubmission = 1並且campus_id = 1）