如何將數組元素從一個對象匹配到另一個對象？

Question

如何編寫適當的函數以將Calendar_ID繁忙數組從響應匹配到客戶端日歷數組項？

這是我從服務器收到的代碼：

初始化對象nr 1

response = {
  calendars: {
    calendarID_1: {
      busy: [{},{}]
    },
    calendarID_2: {
      busy: [{},{}]
    },
  },
  ...
}

這是我需要合並數據的代碼：

初始化錯誤2

clients = [
  {
    name: clientName,
    calendars: ["calendarID_1", "calendarID_2"]
  },
  ...
]

這是迭代函數之后的樣子：

輸出arr應為

clients = [
  {
    name: clientName,
    calendars: {
      calendarID_1: {
        busy: [{}, {}]
      },
      calendarID_2: {
        busy: [{}, {}]
      },
    }
  },
  ...
]

我的嘗試是：

for (const calendar in response.calendars) {
    for (const client in clients) {
        clients[client].calendars.reduce((acc, cur) => {
            if (cur === calendar) {
                 acc[cur] = response.calendars[calendar];
            }
        });
    }
}

Answer 1

 // Input: const response = { calendars: { calendarID_1: { content: "of calendar 1", }, calendarID_2: { content: "of calendar 2", }, calendarID_3: { content: "of calendar 3", }, }, } const clients = [ { name: "first", calendars: ["calendarID_1", "calendarID_2"] }, { name: "second", calendars: ["calendarID_3"] }, ] // Solution: const result = clients.map(client => ({ ...client, calendars: Object.fromEntries( client.calendars.map(id => ([ id, response.calendars[id] ])) ), })); console.log(result); 

這映射到一個新的客戶端數組，散布以前的客戶端，該客戶端基本上是淺表復制整個數組，然后獲取客戶端日歷的id，在響應中查找它們並從中建立一個新對象。 這是客戶日歷ID數量的O（n）。