[英]Problem using greedy and non-greedy regular expressions
我不明白我在做什么錯。 我只需要提取router_name和端口號。 路由器名稱為“ C1900_ROUTER1_SR7
”,端口為“ C1900_ROUTER1_SR7
”,並且可能存在“ B:C1900_ROUTER1_SR7
......”而不是“ A:C1900_ROUTER1_SR7
..........”
string = "A:C1900_ROUTER1_SR7#
A:C1900_ROUTER1_SR7# echo "<team:script>"
<team:script>
A:C1900_ROUTER1_SR7# /environment no more
A:C1900_ROUTER1_SR7#
A:C1900_ROUTER1_SR7# show port 4/1/4
"
regex_S2 = '(A|B):(?P<routername>.*?)#\s*show port\s*(?P<port>.*?)\s*\n'
match_L0_iter = re.findall(regex_S2, string, flags=re.DOTALL)
捕獲的路由器名稱組結果= "C1900_ROUTER1_SR7# A:C1900_ROUTER1_SR7# echo "<pnm:script>" <pnm:script> A:C1900_ROUTER1_SR7# /environment no more A:C1900_ROUTER1_SR7# A:C1900_ROUTER1_SR7"
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.