![](/img/trans.png)
[英]Eloquent relation setup, two foreign keys to same table laravel 5.2
[英]How to properly create a relationship two foreign keys referencing same table in Laravel Eloquent?
我已經在代碼中如下創建了Relationshiop。 在“票證”表中,我使用了兩個引用“用戶”表的外鍵。 當我使用票證模型中的operator nad creator方法時,它可以正常工作。 但是,當我想從用戶模型獲取ownerTickets或operatorTickets時,我會得到null。 我不確定是否正確調用了這些方法。
我的數據庫已滿,我看到該用戶是所有者或操作員。
class CreateTicketsTable extends Migration
{
public function up()
{
Schema::create('tickets', function (Blueprint $table) {
$table->increments('id');
$table->integer('owner_id')->unsigned();
$table->integer('operator_id')->unsigned()->nullable();
$table->timestamps();
$table->foreign('owner_id')->references('id')->on('users');
$table->foreign('operator_id')->references('id')->on('users');
});
}
/*...*/
}
class CreateUsersTable extends Migration
{
public function up()
{
Schema::create('users', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->string('email')->unique();
$table->timestamp('email_verified_at')->nullable();
$table->string('password');
$table->integer('position_id')->unsigned();
$table->rememberToken();
$table->timestamps();
$table->foreign('position_id')->references('id')->on('positions');
});
}
/*...*/
}
class Ticket extends Model {
/*...*/
public function owner() {
return $this->belongsTo(User::class, 'owner_id');
}
public function operator() {
return $this->belongsTo(User::class, 'operator_id');
}
}
class User extends Authenticatable {
/*...*/
public function ownerTickets() {
return $this->hasMany(Ticket::class, 'owner_id', 'id');
}
public function operatorTickets() {
return $this->hasMany(Ticket::class, 'operator_id', 'id');
}
}
Eloquent模型和這種關系是否有好的解決方案? 我應該改變它嗎?
您顯示的是一個很好的解決方案,無需更改它。
關系可以正常工作,例如使用以下代碼:
$user = User::find(1);
echo 'Owner ticket count: ' . $user->ownerTickets->count() . '<br>';
echo 'Operator ticket count: ' . $user->operatorTickets->count() . '<br>';
$ticket = Ticket::find(1);
echo 'Ticket owner ID: ' . $ticket->owner->id . '<br>';
echo 'Ticket operator ID: ' . $ticket->operator->id . '<br>';
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.