[英]Convert a nested dictionary into list of tuples
我有一dictionary
——
d={'revenues':
{
'201907':
{'aaa.csv':'fdwe34x2'},
'201906':{'ddd.csv':'e4c5q'}
},
'complaints':
{'2014':
{'sfdwa.csv','c2c2jh'}
}
}
我想把它轉換成tuples
list
-
[
('revenues','201907','aaa.csv','fdwe34x2'),
('revenues','201906','ddd.csv','e4c5q'),
('complaints','2014','sfdwa.csv','c2c2jh')
]
我嘗試使用list comprehensions
,但沒有幫助 -
l = [(k,[(p,q) for p,q in v.items()]) for k,v in d.items()]
print(l)
[('revenues', [('201907', {'aaa.csv': 'fdwe34x2'}), ('201906', {'ddd.csv': 'e4c5q'})]),
('complaints', [('2014', {'c2c2jh', 'sfdwa.csv'})])]
有什么建議?
如果您不確定此列表可能有多少個級別,則似乎您需要的是遞歸:
def unnest(d, keys=[]):
result = []
for k, v in d.items():
if isinstance(v, dict):
result.extend(unnest(v, keys + [k]))
else:
result.append(tuple(keys + [k, v]))
return result
友情提示:在 Python 3.6 之前,不維護 dict 順序。
[('complaints', '2014', 'sfdwa.csv', 'c2c2jh'),
('revenues', '201906', 'ddd.csv', 'e4c5q'),
('revenues', '201907', 'aaa.csv', 'fdwe34x2')]
您可以遍歷字典的級別:
[(x, y, z) for x in d for y in d[x] for z in d[x][y]]
您可以使用列表推導式來完成,但它會非常復雜,如果結構發生變化,也不容易維護。 除非您特別需要良好的性能,否則我建議使用通用遞歸函數:
def unnest(d, keys=[]):
result = []
if isinstance(d, dict):
for k, v in d.items():
result.extend(unnest(v, keys + [k]))
elif isinstance(d, list):
result.append(tuple(keys + d))
elif isinstance(d, set) or isinstance(d, tuple):
result.append(tuple(keys + list(d)))
else:
result.append(tuple(keys + [d]))
return result
作為獎勵,除了提供的示例中的集合之外,我還在遞歸期間支持列表和元組。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.