[英]How to remove objects and pointers from vector of pointers by object parameter
我有一個指向Event對象的指針向量,如下所示:
std::vector <Event*> event_queue_;
這是我的活動課
class Event{
...
bool IsAlarmSensitiveEvent();
bool alarm_sensitive_event_;
...
};
當alarm_sensitive_event_為true時,我想從指針和Event對象的向量中刪除指針。
我試圖這樣做:
for (Event* x : event_queue_)
{
if (x != nullptr)
{
for (int i = 0; i < event_queue_.size(); i++)
{
if (event_queue_.at(i)->IsAlarmSensitiveEvent())
{
std::cout << "Removing event " << event_queue_.at(i)->NameOfEvent() << std::endl;
delete event_queue_.at(i);
event_queue_.erase(event_queue_.begin() + i);
removed = true;
}
}
}
}
它正在工作,但是我認為循環並不是最好的方法,因此我正在尋找更好的東西。
使用此答案作為指導,您可以划分元素以首先刪除,刪除它們,然后從向量中刪除它們:
#include <vector>
#include <algorithm>
//…
// Partition the elements to delete (place the items to delete on right side of vector)
auto iter = std::stable_partition(event_queue.begin(), event_queue.end(),
[](Event *x) { return !x->IsAlarmSensitiveEvent(); });
// Deallocate them
std::for_each(iter, event_queue.end(), [](Event *x)
{
std::cout << "Removing event " << x->NameOfEvent() << "\n";
delete x;
});
// Erase them from vector
event_queue.erase(iter, event_queue.end());
//...
如果我有auto* event_queue_ = new vector<Event>
而不是vector <Event*> event_queue_
怎么vector <Event*> event_queue_
?
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