[英]android Kotlin: tab long click listener
我正在為如何在我的選項卡上實現長按而苦苦掙扎。 我嘗試了幾種不同的方法,但似乎都不起作用。
我確信它可能是一些基本的東西,或者我根本不理解 tablayout 和尋呼機的點擊。
我在這里發現了一些問題,但它們並不是指長按。
這是我嘗試過的一些事情。
main_tab_pager.iterator().forEach {
view ->
view.setOnLongClickListener{
Toast.makeText(applicationContext, "....", Toast.LENGTH_LONG).show()
true
}
main_tabs.setOnLongClickListener {
when(main_tabs.selectedTabPosition) {
0-> Toast.makeText(applicationContext, "tab 0", Toast.LENGTH_LONG).show()
1-> Toast.makeText(applicationContext, "tab 1", Toast.LENGTH_LONG).show()
2-> Toast.makeText(applicationContext, "tab 2", Toast.LENGTH_LONG).show()
}
true
}
main_tab_pager.setOnLongClickListener {
when(main_tab_pager.currentItem) {
0-> Toast.makeText(applicationContext, "tab 0", Toast.LENGTH_LONG).show()
1-> Toast.makeText(applicationContext, "tab 1", Toast.LENGTH_LONG).show()
2-> Toast.makeText(applicationContext, "tab 2", Toast.LENGTH_LONG).show()
}
true
}
選項卡/尋呼機設置代碼。
main_tab_pager.adapter = TabAdapter(supportFragmentManager, sections)
main_tabs.setupWithViewPager(main_tab_pager)
標簽適配器
class TabAdapter(fragmentManager: FragmentManager, private val sections:
Array<BaseFragment>) : FragmentPagerAdapter(fragmentManager)
{
override fun getItem(position: Int): Fragment {
return sections[position]
}
override fun getCount(): Int {
return sections.size
}
override fun getPageTitle(position: Int): CharSequence? {
return sections[position].title
}
}
感謝Mike M.
val tabs = main_tabs.getChildAt(0) as LinearLayout
for (i in 0 until tabs.childCount) {
when(i){
0 -> tabs.getChildAt(0).setOnLongClickListener {
Toast.makeText(baseContext, "tab 0 ", Toast.LENGTH_LONG).show()
true
}
1 -> tabs.getChildAt(1).setOnLongClickListener {
Toast.makeText(baseContext, "tab 1", Toast.LENGTH_LONG).show()
true
}
2 -> tabs.getChildAt(2).setOnLongClickListener {
Toast.makeText(baseContext, "tab 2", Toast.LENGTH_LONG).show()
true
}
}
}
val tabs = recylerbin_tabLayout.getChildAt(0) as LinearLayout
for (i in 0 until tabs.childCount) {
tabs.getChildAt(i).setOnLongClickListener {
true
}
}
}
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