[英]Allow the user to input the list position of the word to RETURN to 2nd and 3rd element from the list
我需要有人幫助我,而無需使用外部庫對此進行編碼熊貓進口異常計數器
lineList = [['Cat', 'c', 1, x],['Cat', 'a', 2, x],['Cat', 't', 3, x],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]
二維列表中出現次數超過2次的單詞顯示在數字列表中
例如:
1. Cat
2. Bat
如何允許用戶通過輸入列表位置編號來選擇單詞? 因此,例如,如果用戶輸入1,它將在嵌套列表中返回Cat的第二個和第三個元素:
c = 1, a = 2, t = 3
我是Python的初學者,所以不確定如何解決此問題。
您可以使用str.join
, str.format
, enumerate
和一個生成器表達式 :
word_counts = [['Cat', 2], ['Bat', 3], ['Fat', 1], ['Mat', 1]]
filtered = [p for p in word_counts if p[1] > 1]
print('\n'.join('{0}. {1}'.format(i, p[0]) for i, p in enumerate(filtered, 1)))
輸出:
1. Cat
2. Bat
對於特定位置的字符串:
n = int(input('position: ')) # 1-indexed
print('{0}. {1}'.format(n, filtered[n - 1][0])) # 0-indexed (hence, n - 1)
使用Counter
對單詞進行計數,然后使用enumerate
為列表添加數字:
from collections import Counter
lineList = [['Cat', 'c', 1, 2],['Cat', 'c', 1, 3],['Bat', 'b', 1, 4],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]
counts = Counter(word for word, *other_stuff in lineList)
filtered = [word for word, count in counts.items() if count >= 2]
for number, word in enumerate(filtered, start=1):
print("{: >2}.".format(number), word)
版畫
1. Cat
2. Bat
如果您無法導入Counter
,則可以很容易地編寫一個基本的替代品:
def Counter(seq):
d = {}
for item in seq:
d[item] = d.get(item, 0) + 1
return d
( Counter
具有更多功能,但這就是我們正在使用的全部)
然后,您可以選擇一個單詞:
def choose(filtered):
while True:
choice = input("Select a word: ")
try:
choice = int(choice)
return filtered[choice-1]
except ValueError, IndexError:
print("Please enter a number on the list")
您就在那里,只需檢查嵌套列表中第二項的值是否大於1。
list1 = [['Cat', 2], ['Bat', 3], ['Fat', 1], ['Mat', 1]]
index = 1
for i in range(len(list1)):
if list1[i][1] > 1:
print (str(index)+ ". " + str(list1[i][0]))
index += 1
打印:
1. Cat
2. Bat
您對說明做了一些更改,所以我重寫了答案以使其更合適
lineList = [['Cat', 'c', 1, 'x'],['Cat', 'a', 2, 'x'],['Cat', 't', 3, 'x'],['Bat', 'b', 1, 3],['Bat', 'b', 1, 2],['Mat', 'm', 1, 1],['Fat', 'f', 1, 13]]
#First we create a dictionary with the repeating words in the list you gave
nameList = []
frequencyDict = {}
for i in range(len(lineList)):
if lineList[i][0] in frequencyDict.keys():
frequencyDict[lineList[i][0]] += 1
else:
frequencyDict[lineList[i][0]] = 1
#this will give you a list with the order
#it will be useful to get the indices of the repeating word later
nameList.append(lineList[i][0])
# Printing a list of values when if they are repeated
index = 1
repeats = []
for i in frequencyDict.keys():
if frequencyDict[i] > 1: #This if statement checks if it was repeated or not
print(str(index)+ ". " + i)
repeats.append(i) # we also crete yet another list so the user can call it with his input later
index += 1
x = (int(input("Which item on the list would you like to know more information about: \n")) -1) #note that we are subtracting one from the input so it matches the index of the list
# Here I am trying to get all the indices that start with the word that user replied
indicesList = []
for i in range(len(nameList)):
if nameList[i] == repeats[x]:
indicesList.append(i)
# Here I am printing the value that is in the index 1 and 2 of the nested list in Linelist
for i in range(len(indicesList)):
print(str(lineList[indicesList[i]][1]) +
" = " +
str(lineList[indicesList[i]][2]))
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