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我如何打印一行 x 次,其中 x 是該行中的一個值?

[英]How do i print a row x amout of times, where x is a value in this row?

我正在用 sql 查詢的內容填充 iReport,有問題的查詢需要返回訂單行 x 次,其中 x 是 order.qty 的值。

這是有問題的查詢:

select ol.order_id, i.title, i.desc, s.ean, ol.curr, ol.price, i.qty
FROM inventory i
LEFT JOIN dcsdba.sku s
ON (s.title    = i.title
AND s.client_id = i.client_id)
INNER JOIN order_container oc
ON (i.client_id    = oc.client_id
AND i.container_id = oc.container_id)
INNER JOIN order_header oh
ON (oh.order_id  = oc.order_id
AND oh.client_id = oc.client_id)
inner join order_line ol
on (ol.order_id = oc.order_id
and ol.client_id = oh.client_id)
WHERE i.container_id = 'CONTAINER1'
AND i.client_id      = 'TEST'
AND rownum <= i.qty

在這個例子中 i.qty 是 3

我目前的結果是:

order_id | title | desc | ean | curr | price | qty
__________________________________________________
order_1  | title1| desc1| ean1|curr1 | price1| qty1

我需要的是:

order_id | title | desc | ean | curr | price | qty
__________________________________________________
order_1  | title1| desc1| ean1|curr1 | price1| qty1
order_1  | title1| desc1| ean1|curr1 | price1| qty1 
order_1  | title1| desc1| ean1|curr1 | price1| qty1 


附注。 我不能使用視圖或循環。

您可以使用以下查詢來實現相同的目的:

create table tabl(id, X) as
(select 1, 2 from dual
union all
select 2,5 from dual);

select id, x from
(select distinct id, x, level
from tabl
connect by level <= x)
order by id;

db<>小提琴演示

干杯!!

是這樣解決的:

with DETAILS AS (select
  i.title,
  i.Desc,
  s.ean,
  ol.curr,
  ol.price,
  i.qty
FROM inventory i
LEFT JOIN title s
ON (s.title = i.title
AND s.client_id = i.client_id)
INNER JOIN order_container oc
ON (i.client_id    = oc.client_id
AND i.container_id = oc.container_id)
INNER JOIN order_header oh
ON (oh.order_id  = oc.order_id
AND oh.client_id = oc.client_id)
INNER JOIN order_line ol
ON (ol.order_id      = oc.order_id
AND ol.client_id     = oh.client_id)
where i.container_id = 'DT1'
and i.client_id = 'TEST')
select * from DETAILS d,
(select rownum repeat from dual CONNECT BY LEVEL<=(select max(qty) from DETAILS))r
where D.qty>=r.repeat
order by d.title, r.repeat;

感謝@Tejash 按級別顯示連接

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