如何將變量（laravel）傳遞給 javascript？

Question

因此，我需要將兩個變量從 laravel（ $event->latitude event- $event->latitude和$event->longitude event- $event->longitude ）傳遞給 Javascript，因為我需要將此值用於 Google Maps。這些是 2 個值，例如... latitude : 44.4590762 和 longitude ： 26.0967384000000。

所以，我試圖做的......

var mylat = {!! json_encode($event->latitude->toArray()) !!};
var mylng = {!! json_encode($event->longitude->toArray()) !!};

or 

var mylat = {!! $event->latitude !!}
var mylng = {!! $event->longitude !!}

但沒有結果。我的變量仍然沒有值。

這是我的事件控制器：

$event->longitude = $request['longitude'];
$event->latitude = $request['latitude'];

我的看法：

<div id="map"></div>

我的腳本：

<script>
    var mylat = {!! json_encode($event->latitude->toArray()) !!};
    var mylng = {!! json_encode($event->longitude->toArray()) !!};


function initMap() {
    var map = new google.maps.Map(document.getElementById('map'), {
      center: {lat: mylat, lng: mylng},
      zoom: 18
    });
    var input = document.getElementById('searchInput');
    map.controls[google.maps.ControlPosition.TOP_LEFT].push(input);

    var autocomplete = new google.maps.places.Autocomplete(input);
    autocomplete.bindTo('bounds', map);

    var infowindow = new google.maps.InfoWindow();
    var marker = new google.maps.Marker({
        map: map,
        anchorPoint: new google.maps.Point(0, -29)
    });

    autocomplete.addListener('place_changed', function() {
        infowindow.close();
        marker.setVisible(false);
        var place = autocomplete.getPlace();
        if (!place.geometry) {
            window.alert("Autocomplete's returned place contains no geometry");
            return;
        }

        // If the place has a geometry, then present it on a map.
        if (place.geometry.viewport) {
            map.fitBounds(place.geometry.viewport);
        } else {
            map.setCenter(place.geometry.location);
            map.setZoom(17);
        }
        marker.setIcon(({
            url: place.icon,
            size: new google.maps.Size(71, 71),
            origin: new google.maps.Point(0, 0),
            anchor: new google.maps.Point(17, 34),
            scaledSize: new google.maps.Size(35, 35)
        }));
        marker.setPosition(place.geometry.location);
        marker.setVisible(true);

        var address = '';
        if (place.address_components) {
            address = [
              (place.address_components[0] && place.address_components[0].short_name || ''),
              (place.address_components[1] && place.address_components[1].short_name || ''),
              (place.address_components[2] && place.address_components[2].short_name || '')
            ].join(' ');
        }

        infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
        infowindow.open(map, marker);

        //Location details
        for (var i = 0; i < place.address_components.length; i++) {
            if(place.address_components[i].types[0] == 'postal_code'){
                document.getElementById('postal_code').innerHTML = place.address_components[i].long_name;
            }
            if(place.address_components[i].types[0] == 'country'){
                document.getElementById('country').innerHTML = place.address_components[i].long_name;
            }
        }
        document.getElementById('location').innerHTML = place.formatted_address;
        document.getElementById('lat').innerHTML = place.geometry.location.lat();
        document.getElementById('lon').innerHTML = place.geometry.location.lng();
        document.getElementById('location').innerHTML = place.geometry.location.location();
    });
}
</script>

Answer 1

將$event存儲在 javascript 變量中使用它。

Answer 2

正確的解決方案是這樣的：我在我的視圖中用 php 創建了變量：

<?php $latitude =  $event->latitude  ?>
<?php $longitude =  $event->longitude  ?>

這是我在腳本中的變量：

var mylat = <?= $latitude ?>;
var mylng = <?= $longitude ?>;