Javascript-將JavaScript對象數組轉換為排序的鍵/值javascript對象

Question

我有一個不確定大小的javascript對象數組：

var arr = [      
 {
        "Entities": 
          [
            {
              "BeginOffset": 28,
              "EndOffset": 35,
              "Score": 0.9945663213729858,
              "Text": "Tunisie",
              "Type": "LOCATION"
            },
            {
              "BeginOffset": 60,
              "EndOffset": 71,
              "Score": 0.8412493228912354,
              "Text": "Al HuffPost",
              "Type": "PERSON"
            },
            {
              "BeginOffset": 60,
              "EndOffset": 71,
              "Score": 0.9412493228912354,
              "Text": "trump",
              "Type": "PERSON"
            } 
          ],
        "File": "article1.com"
 },
 {
        "Entities": 
          [
            {
              "BeginOffset": 28,
              "EndOffset": 35,
              "Score": 0.9945663213729858,
              "Text": "france",
              "Type": "LOCATION"
            },
            {
              "BeginOffset": 60,
              "EndOffset": 71,
              "Score": 0.7412493228912354,
              "Text": "john locke",
              "Type": "PERSON"
            },
            {
              "BeginOffset": 60,
              "EndOffset": 71,
              "Score": 0.9412493228912354,
              "Text": "sawyer",
              "Type": "PERSON"
            } 
          ],
        "File": "anotherarticle.com"
      },
      {
        //and so on ...
 }
]

如何將其轉換為鍵/值Javascript對象，其中每個文件給出與其相關聯的Persons數組，而此數據僅根據type =“ person”進行過濾，並且得分> 0.8，並通過以最高分 （實體的PERSON大於1）。

例如，上面的示例應輸出：

var finalObject =    {
  "article1.com": ["trump", "Al HuffPost"],//tunisisa not here because entity is a LOCATION
  "anotherarticle.com": ["sawyer"] //john locke not here because score <0.8
}

我嘗試過以各種方式進行縮小，映射和過濾，但始終失敗。

Answer 1

下面的代碼通過將輸入數組簡化為一個對象，過濾掉不需要的實體，基於得分進行反向排序，並將其余實體映射到它們的Text屬性，來創建請求的輸出：

const result = arr.reduce((a, {Entities, File}) => {
  a[File] = Entities
              .filter(({Type, Score}) => Type === 'PERSON' && Score > 0.8)
              .sort((a, b) => b.Score - a.Score)
              .map(({Text}) => Text);
  return a;
}, {});

---

完整代碼段：

 const arr = [{ "Entities": [{ "BeginOffset": 28, "EndOffset": 35, "Score": 0.9945663213729858, "Text": "Tunisie", "Type": "LOCATION" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.8412493228912354, "Text": "Al HuffPost", "Type": "PERSON" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.9412493228912354, "Text": "trump", "Type": "PERSON" } ], "File": "article1.com" }, { "Entities": [{ "BeginOffset": 28, "EndOffset": 35, "Score": 0.9945663213729858, "Text": "france", "Type": "LOCATION" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.7412493228912354, "Text": "john locke", "Type": "PERSON" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.9412493228912354, "Text": "sawyer", "Type": "PERSON" } ], "File": "anotherarticle.com" } ]; const result = arr.reduce((a, {Entities, File}) => { a[File] = Entities .filter(({Type, Score}) => Type === 'PERSON' && Score > 0.8) .sort((a, b) => b.Score - a.Score) .map(({Text}) => Text); return a; }, {}); console.log(result); 

Answer 2

對於每個對象，請執行以下操作。

• 獲取用作密鑰的文件名
• 根據您的要求過濾Entities （類型=“人”且得分> 0.8）
• 然后按分數對過濾后的實體進行排序
• 然后將排序后的實體映射到它們的名稱並生成names數組
• 將其分配為文件名鍵下的值

 var arr = [ { "Entities": [ { "BeginOffset": 28, "EndOffset": 35, "Score": 0.9945663213729858, "Text": "Tunisie", "Type": "LOCATION" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.8412493228912354, "Text": "Al HuffPost", "Type": "PERSON" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.9412493228912354, "Text": "trump", "Type": "PERSON" } ], "File": "article1.com" }, { "Entities": [ { "BeginOffset": 28, "EndOffset": 35, "Score": 0.9945663213729858, "Text": "france", "Type": "LOCATION" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.7412493228912354, "Text": "john locke", "Type": "PERSON" }, { "BeginOffset": 60, "EndOffset": 71, "Score": 0.9412493228912354, "Text": "sawyer", "Type": "PERSON" } ], "File": "anotherarticle.com" } ]; function createObject() { var result = {}; arr.forEach(function (item) { var fileName = item['File']; result[fileName] = item["Entities"] .filter(function (entity) { return (entity['Type'] === 'PERSON' && entity['Score'] > 0.8) }) .sort(function (entity1, entity2) { return (entity1['Score'] > entity2['Score']) ? -1 : 1; }) .map(function (entity) { return entity['Text'] }); }); console.log(result); } createObject();