如何再次合並已破壞的對象鍵？

Question

如您所見，我必須銷毀吸氣劑，將它們求和並獲得多少收入。

這是一個示例代碼，它是Vuex商店中的吸氣劑，但這並不重要，它與javascript有關，而不是vue本身。

    sumIncomes: (
      {
        incomeMonthlyNet,
        incomePension,
        incomeChildBenefit,
        incomeChildSupports,
        incomeSpousalMaintenance,
        incomeParentalBenefit,
        incomeSecondaryWork,
        incomeSelfEmployedWork,
        incomeMiniJob,
        incomeSupplementaryPension,
        incomeRental,
      }
    ) => {
      return (
        incomeMonthlyNet +
        incomePension +
        incomeChildBenefit +
        incomeChildSupports +
        incomeSpousalMaintenance +
        incomeParentalBenefit +
        incomeSecondaryWork +
        incomeSelfEmployedWork +
        incomeMiniJob +
        incomeSupplementaryPension +
        incomeRental
      )
    },

這看起來一點也不優雅，但是我突然找不到更好的方法（例如，如果我可以將分解對象存儲在變量中，那么我可以使用Object.values並減少它，但是我不這樣做）不知道這樣）

謝謝你的幫助 ;）

Answer 1

是的，您可以，這里有一些優雅的聲明式方法

sumIncomes: (
      incomeObject
    ) => {
      // If your object only contain income Properties you can do this
      return Object.values(incomeObject).reduce((acc, cur) => acc + cur,0)

      // If your object contain other keys and you know that income Properties all
      // have number values you can do this
      return Object.keys(incomeObject).reduce((acc, key) => key.startsWith('income') ? acc + incomeObject[key] : acc ,0)

      // if none of the above works because in your object you have a prop called for example incomeTest and 
      // its value is a string then you can do this
      const arrOfPropsToSum = ['incomeMonthlyNet',
        'incomePension',
        'incomeChildBenefit',
        'incomeChildSupports',
        'incomeSpousalMaintenance',
        'incomeParentalBenefit',
        'incomeSecondaryWork',
        'incomeSelfEmployedWork',
        'incomeMiniJob',
        'incomeSupplementaryPension',
        'incomeRental']
      return arrOfPropsToSum.reduce((acc, propKey) =>  acc + incomeObject[propKey], 0)
    },

這里有3條return語句，很明顯，除非您注釋第一個，否則永遠不會到達第二個和第三個。 您可以通過注釋第三個來嘗試第二個，而通過注釋第一個和第二個來嘗試第三個。