如何在mongodb中根據日期范圍過濾數據

Question

[{
    "_id": {
        "$oid": "5d7a76c94c3c8c05618cef58"
    },
    "title": "hello",
    "date": {
        "$date": "2019-06-07T07:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a7809ef31980615ed3756"
    },
    "title": "hello",
    "date": {
        "$date": "2019-06-08T07:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello6",
    "date": {
        "$date": "2019-07-19T08:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello7",
    "date": {
        "$date": "2019-07-03T08:22:00.000Z"
    },
    "__v": 0
}]

我正在使用mongoose將數據存儲在mongodb中，我正在嘗試使用mongoose過濾數據

我想要日期為2019-07-01至2019-07-31所有文檔。我們可以在mongoDB中的mongoose上執行此過濾器嗎

預期產量

[
{
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello6",
    "date": {
        "$date": "2019-07-19T08:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello7",
    "date": {
        "$date": "2019-07-03T08:22:00.000Z"
    },
    "__v": 0
}
]

這是我的代碼https://codesandbox.io/s/lively-tree-hd0fo

app.get("/saveData", async () => {
  try {
    var blog = new BlogPostModel({
      title: "hello6",
      date: "19-Jul-2019 08:22"
    });
    console.log("before save");
    let saveBlog = await blog.save(); //when fail its goes to catch
    console.log(saveBlog); //when success it print.
    console.log("saveBlog save");
  } catch (error) {
    console.log(error);
  }
});

Answer 1

您可以使用MongoDB的$gte （大於或等於）和$lte （小於或等於）：

blog.find({ date: { $gte: '2019-07-01', $lte: '2019-07-31' } });