如何使用冗余鍵將列表列表轉換為字典？

Question

我有一個列表列表，稱為my_list ：

['sit', (1, 1)]
['laboris', (2, 1)]
['nisi', (2, 1)]
['est', (4, 1)]
['qui', (4, 1)]
['cillum', (3, 1)]
['voluptate', (3, 1)]
['eu', (3, 1)]
['irure', (3, 1)]
['sunt', (4, 1)]
['reprehenderit', (3, 1)]
['nulla', (3, 1)]
['sint', (4, 1)]
['fugiat', (3, 1)]
['dolore', (2, 1)]
['dolore', (3, 1)]
['enim', (2, 1)]
['occaecat', (4, 1)]
['tempor', (2, 1)]
['commodo', (2, 1)]
['non', (4, 1)]
['minim', (2, 1)]
['aute', (3, 1)]
['ut', (2, 2)]
['ex', (2, 1)]
['deserunt', (4, 1)]
['ea', (2, 1)]
['eiusmod', (2, 1)]
['culpa', (4, 1)]
['labore', (2, 1)]
['mollit', (4, 1)]
['officia', (4, 1)]
['cupidatat', (4, 1)]
['adipiscing', (2, 1)]
['amet', (1, 1)]
['et', (2, 1)]
['ad', (2, 1)]
['consectetur', (2, 1)]
['anim', (4, 1)]
['magna', (2, 1)]
['quis', (2, 1)]
['ullamco', (2, 1)]
['dolor', (1, 1)]
['dolor', (3, 1)]
['aliquip', (2, 1)]
['velit', (3, 1)]
['ipsum', (1, 1)]
['incididunt', (2, 1)]
['sed', (2, 1)]
['id', (4, 1)]
['esse', (3, 1)]
['exercitation', (2, 1)]
['nostrud', (2, 1)]

我努力了：

d = {}

for item in all_lists:
    d[item[0]] = item[1:]

print (d)

但這會覆蓋一個密鑰，而不是更新該值。 例如， dolor變為： {'dolor': [(3,1)]而不是預期的目標： {'dolor': (3,1), (1,1), etc...}

理想情況下，字典形狀將不包括元組列表作為值，但是如果需要的話。

如何將列表列表轉換為我想要的格式的字典？

我已經觀察到Python：字典的列表列表，但是這使我產生了現在不正確的信息。

Answer 1

使用defaultdict功能：

https://docs.python.org/2/library/collections.html#collections.defaultdict

未經測試的代碼！

d = defaultdict(list)

for item in all_lists:
    d[item[0]].append(item[1:])

print (d)

Answer 2

您可以使用itertools.groupby來對鍵進行排序（看起來像這樣）：

import itertools as it
result = {k: [x[1] for x in v] for k, v in it.groupby(test, key=lambda x: x[0])}

Answer 3

一種方法是，如果d缺少此鍵且值為空列表[] ，則添加新的鍵值對。 然后將新值附加到該列表。

Python具有setdefault來做到這一點。

all_lists = [
    ['sit', (1, 1)],
    ['sit', (2, 2)],
    ['laboris', (2, 1)]
]

d = {}
for key, new_value in all_lists:
    values = d.setdefault(key, [])
    values.append(new_value)

print(d)


{
 'sit': [(1, 1), (2, 2)], 
 'laboris': [(2, 1)]
}

Answer 4

這很煩人，但是您可以通過快速調用構造函數將list更改為tuple 。

a = [
    ['sit', (1, 1)],
    ['laboris', (2, 1)],
    ['nisi', (2, 1)],
    ['est', (4, 1)],
    ['qui', (4, 1)],
    ['cillum', (3, 1)],
    ['voluptate', (3, 1)],
    ['eu', (3, 1)],
    ['irure', (3, 1)],
    ['sunt', (4, 1)],
    ['reprehenderit', (3, 1)],
    ['nulla', (3, 1)],
    ['sint', (4, 1)],
    ['fugiat', (3, 1)],
    ['dolore', (2, 1)],
    ['dolore', (3, 1)],
    ['enim', (2, 1)],
    ['occaecat', (4, 1)],
    ['tempor', (2, 1)],
    ['commodo', (2, 1)],
    ['non', (4, 1)],
    ['minim', (2, 1)],
    ['aute', (3, 1)],
    ['ut', (2, 2)],
    ['ex', (2, 1)],
    ['deserunt', (4, 1)],
    ['ea', (2, 1)],
    ['eiusmod', (2, 1)],
    ['culpa', (4, 1)],
    ['labore', (2, 1)],
    ['mollit', (4, 1)],
    ['officia', (4, 1)],
    ['cupidatat', (4, 1)],
    ['adipiscing', (2, 1)],
    ['amet', (1, 1)],
    ['et', (2, 1)],
    ['ad', (2, 1)],
    ['consectetur', (2, 1)],
    ['anim', (4, 1)],
    ['magna', (2, 1)],
    ['quis', (2, 1)],
    ['ullamco', (2, 1)],
    ['dolor', (1, 1)],
    ['dolor', (3, 1)],
    ['aliquip', (2, 1)],
    ['velit', (3, 1)],
    ['ipsum', (1, 1)],
    ['incididunt', (2, 1)],
    ['sed', (2, 1)],
    ['id', (4, 1)],
    ['esse', (3, 1)],
    ['exercitation', (2, 1)],
    ['nostrud', (2, 1)]
]

final = {}
for l in a:
    final[l[0]]=tuple(l[1:])[0]

print(final)

版畫

{'sit': (1, 1), 'laboris': (2, 1), 'nisi': (2, 1), 'est': (4, 1), 'qui': (4, 1), 'cillum': (3, 1), 'voluptate': (3, 1), 'eu': (3, 1), 'irure': (3, 1), 'sunt': (4, 1), 'reprehenderit': (3, 1), 'nulla': (3, 1), 'sint': (4, 1), 'fugiat': (3, 1), 'dolore': (3, 1), 'enim': (2, 1), 'occaecat': (4, 1), 'tempor': (2, 1), 'commodo': (2, 1), 'non': (4, 1), 'minim': (2, 1), 'aute': (3, 1), 'ut': (2, 2), 'ex': (2, 1), 'deserunt': (4, 1), 'ea': (2, 1), 'eiusmod': (2, 1), 'culpa': (4, 1), 'labore': (2, 1), 'mollit': (4, 1), 'officia': (4, 1), 'cupidatat': (4, 1), 'adipiscing': (2, 1), 'amet': (1, 1), 'et': (2, 1), 'ad': (2, 1), 'consectetur': (2, 1), 'anim': (4, 1), 'magna': (2, 1), 'quis': (2, 1), 'ullamco': (2, 1), 'dolor': (3, 1), 'aliquip': (2, 1), 'velit': (3, 1), 'ipsum': (1, 1), 'incididunt': (2, 1), 'sed': (2, 1), 'id': (4, 1), 'esse': (3, 1), 'exercitation': (2, 1), 'nostrud': (2, 1)}