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JPA 插入外鍵為 null

[英]JPA inserting foreign key as null

好吧,我已經嘗試了所有可以在網上找到的東西,但仍然沒有運氣。

我有2節課。 趨勢圖表和趨勢。 這是 OneToManyMapping。 TrendsChart 可以有多個趨勢。

數據庫:SQL 服務器

趨勢圖表

CREATE TABLE [dbo].[TrendsChart](
    [id] [int] NOT NULL IDENTITY,
    [Name] [varchar] (50) NULL,
PRIMARY KEY CLUSTERED
(
    [id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

趨勢表

CREATE TABLE [dbo].[Trends](
    [TrendsID] [int] NOT NULL IDENTITY,
        [ItemName] [varchar] (100) NULL,
    [chart_id] [int] NULL
PRIMARY KEY CLUSTERED
(
    [TrendsID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

ALTER TABLE [dbo].[Trends]  WITH CHECK ADD  CONSTRAINT [FK_Trends_TrendsChart] FOREIGN KEY([chart_id])
REFERENCES [dbo].[TrendsChart] ([id]) ON DELETE CASCADE
GO
ALTER TABLE [dbo].[Trends] CHECK CONSTRAINT [FK_Trends_TrendsChart]
GO

趨勢圖 Model

@Entity
@Table(name = "TrendsChart")
public class TrendsChart {
    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id;

    @Column(name="Name")
    private String name;

    @OneToMany(mappedBy="trendsChart", cascade = CascadeType.ALL)
    List<Trends> trends = new ArrayList<>();

趨勢 Model

@Entity
@Table(name = "Trends")
public class Trends {
    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    @Column(name="TrendsID")
    private int trendsID;

    @Column(name="ItemName")
    private String itemName;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name ="chart_id", nullable=false, updatable = false, insertable = true,referencedColumnName = "id")
    @OnDelete(action = OnDeleteAction.CASCADE)
    private TrendsChart trendsChart;

在 controller 我正在做

trendsChartRepository.save(trendsChart);

除了chart_id列始終為 null 之外,所有數據均已正確填充

您必須為 TrandChart 積極設置每個趨勢:

@Entity
@Table(name = "TrendsChart")
public class TrendsChart {

   //...

   public void addTrend(Trends trend) {
      this.trends.add(trend);
      trend.setTrendsChart(this);
   }

}

然后保存:

TrendsChart trendsChart = new TrendsChart();
Trends trend = new Trend();
trendsChart.setTrend(trend);
trendsChartRepository.save(trendsChart);

這是關於這個主題的一個很好的教程: https://vladmihalcea.com/the-best-way-to-map-a-onetomany-association-with-jpa-and-hibernate/

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