如何使用 BeautifulSoup 抓取超鏈接標題？

Question

所以，我試圖從中抓取的網站是：https//viewyourdeal-gabrielsimone.com'

產品名稱和價格在每個 div class = "info-wrapper" 下我可以毫無問題地提取價格，但是當我嘗試提取產品標題時，它無法將其轉換為文本作為其 href 鏈接。 每個產品名稱都在 href 下的 div class 下。 所以我的問題是，我如何抓取產品名稱？

import json
from bs4 import BeautifulSoup
import requests 
import csv
from datetime import datetime

url = 'https://viewyourdeal-gabrielsimone.com'

gmaInfo=[]
response = requests.get(url, timeout=5)
content = BeautifulSoup(response.content, "html.parser")
for info in content.findAll('div', attrs={"class" : "wrapper ease-animation"}):
    gridObject = {
            "title" : info.find('div', attrs={"class" : "title animation allgrey"}),
            "price" : info.find('span', attrs={"class":"red-price"}).text
            }
    print(gridObject)
    with open('index.csv', 'w') as csv_file:
        writer = csv.writer(csv_file)
        writer.writerow([gridObject])

Answer 1

使用以下代碼，很少有項目返回為 None。如果元素存在，只需提供 If 條件即可獲取文本。

from bs4 import BeautifulSoup
import requests
import csv
from datetime import datetime

url = 'https://viewyourdeal-gabrielsimone.com'

gmaInfo=[]
response = requests.get(url, timeout=5)
content = BeautifulSoup(response.content, "html.parser")

for info in content.findAll('div', attrs={"class" : "wrapper ease-animation"}):
   if info.find('div', attrs={"class": "title animation allgrey"}):
     gridObject = {
            "title" : info.find('div', attrs={"class" : "title animation allgrey"}).text.strip(),
            "price" : info.find('span', attrs={"class":"red-price"}).text
            }
     print(gridObject)
     with open('index.csv', 'w') as csv_file:
        writer = csv.writer(csv_file)
        writer.writerow([gridObject])

Answer 2

我對我的 div class 過於具體，我將 class 更改為簡單的標題，它工作正常。