[英]I need to make this java code repeat based on the user input and I cannot make it repeat using the code that I do have so far
我需要根據用戶輸入重復此 java 代碼,並且我無法使用我目前擁有的代碼使其重復。 除了掃描儀之外,我不應該使用任何其他進口產品並使用 class 主要產品。 這是因為我們使用https://repl.it/languages/java10作為我們的編譯器,因為我們是基本的 class。 當我運行代碼時,它應該詢問十個隨機加減法,並且應該詢問用戶是否要繼續。 當輸入 1 繼續時,它應該再問十個問題。 但是,在運行此代碼時,它會在第一個問題之后停止。
import java.util.Scanner;
class Main {
public static void main(String[] args) {
System.out.println("Answer the following questions.");
Scanner in = new Scanner(System.in);
int A = 0;
int N = 10;
int n = 0;
int H = 0;
boolean p = true;
while (p){
int R1 = (int)(Math.random() * 50 + 1);
int R2 = (int)(Math.random() * 999 + 1);
int R3 = (int)(Math.random() * 999 + 1);
if(R1>25){
System.out.println( "" + R2 + " + " + R3);
A = in.nextInt();
if (A == (R2 + R3))
System.out.println("Correct");
else
System.out.println("Incorrect");
}
if(R1<25){
System.out.println( "" + R2 + " - " + R3);
A = in.nextInt();
if (A == (R2 - R3))
System.out.println("Correct");
else
System.out.println("Incorrect");}
N--;
if (N==0)
p = false;
continue;
}System.out.println("Do you want ot continue? Put 1 for yes, 2 for no.");
H = in.nextInt();
if (H==1)
p=true;
else
p=false;
while (N>0);
}
}
這就是為什么你提出這個問題System.out.println("Do you want ot continue? Put 1 for yes, 2 for no.");
出了while
。 我建議使用do while
不是while
。 因此,您只需將問題放在循環do while
中。
System.out.println("Answer the following questions.");
Scanner in = new Scanner(System.in);
int A = 0;
int N = 10;
int H = 0;
boolean p = true;
do{
int R1 = (int) (Math.random() * 50 + 1);
int R2 = (int) (Math.random() * 999 + 1);
int R3 = (int) (Math.random() * 999 + 1);
if (R1 > 25) {
System.out.println("" + R2 + " + " + R3);
A = in.nextInt();
if (A == (R2 + R3)) {
System.out.println("Correct");
} else {
System.out.println("Incorrect");
}
}
if (R1 < 25) {
System.out.println("" + R2 + " - " + R3);
A = in.nextInt();
if (A == (R2 - R3)) {
System.out.println("Correct");
} else {
System.out.println("Incorrect");
}
}
N--;
System.out.println("Do you want ot continue? Put 1 for yes, 2 for no.");
H = in.nextInt();
if (H == 1) {
p = true;
} else {
p = false;
}
if (N == 0) {
p = false;
System.out.println("You have reached your max attempts.")
}
}while (N > 0 && p);
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