如何在具有許多條件的“for”子句中找到 python 中的完全匹配？

Question

例如，我有這個列表：

full_text = ["This is Archie. He is a rare Norwegian Pouncing Corgo.", 
"This is Darla. She commenced a snooze mid meal.", 
"Here we have a majestic great"]

我想將第一個子句標識為包含“He”，將第三個子句標識為不包含“He”。

但我不知道如何在這段代碼中使用正則表達式：

gender = []

for f in full_text:
    words = f.split(" ")
    if any (["He" in f, "boy" in f, "him" in f, "his" in words]):
        gender.append(0)
    elif any (["She" in f, "girl" in f, "her" in f, "hers" in words]):
        gender.append(1)
    else:
        gender.append(-1)

我得到的結果是 [0, 1, 1]。 我想要的結果是 [0, 1, -1]。

Answer 1

評論：..由於區分大小寫更精確

我同意，更籠統地說，你的 const，例如["he", "boy", "him", "his"]和words , ["here", "we", "have"]應該都是小寫的。

---

問題：你能用文字說明你在哪里寫的嗎？

gender = []

for f in full_text:
    words = f.split(" ")
    if any ([term in words for term in ["He", "boy", "him", "his"]]):
        gender.append(0)
    elif any ([term in words for term in ["She", "girl", "her", "hers"]]):
        gender.append(1)
    else:
        gender.append(-1)

print(gender)  
>>> [0, 1, -1]

---

OOP解決方案：使用早斷。

class Gender:
    male = ["He", "boy", "him", "his"]
    female = ["She", "girl", "her", "hers"]

    def __init__(self, words):
        self.value = -1
        for value, terms in enumerate([Gender.male, Gender.female]):
            if self.match(words, terms):
                self.value = value
                break

    def match(self, words, terms):
        for term in terms:
            if term in words:
                return True
        return False      

gender = []

for f in full_text:
    words = f.split(" ")
    gender.append(Gender(words).value)

print(gender)  
>>> [0, 1, -1]