如何在 Java Rest API 中獲取真實路徑 InputStream 文件

Question

I have a Java Rest API Post method that sends an image (InputStream) as a parameter, and I have to save it in a blob column in Oracle.

我需要獲取此 InputStream 的完整路徑（真實路徑）才能將此圖像保存在數據庫中。 我的代碼如下。

@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
                @FormDataParam("file") InputStream uploadedInputStream,
                @FormDataParam("file") FormDataContentDisposition fileDetail) {
String UPLOAD_FOLDER = "c:/uploadedFiles/"; // my rest api does not have this file, how to get at runtime?    
String uploadedFileLocation = UPLOAD_FOLDER + fileDetail.getFileName(); // this line is ok

我想做這樣的事情：

String UPLOAD_FOLDER = uploadedInputStream.getRealPathName();

或者

String UPLOAD_FOLDER = fileDetail.getRealPathName();

Answer 1

我通過將輸入流轉換為字節數組解決了這個問題。 我將 byte[] 轉發到數據庫持久化方法。 我的代碼如下：

public byte[] toByteArray(InputStream is) throws IOException{
    ByteArrayOutputStream baus = new ByteArrayOutputStream();
    byte[] buffer = new byte[1024];
    int len;
    while((len= is.read(buffer)) != -1){
        baus.write(buffer, 0, len);
    }
    return baus.toByteArray();
}

@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
                @FormDataParam("file") InputStream uploadedInputStream,
                @FormDataParam("file") FormDataContentDisposition fileDetail) {
    ...
    byte[] b = toByteArray(uploadedInputStream);
    business.saveUploadedFileInDatabase(b);
    ...
}

public boolean uploadFile(byte[] b) throws SQLException, IOException{
    ...
    PreparedStatement ps = conn.prepareStatement("INSERT INTO TABLE_IMAGE_TEST (CODE, IMAGE) VALUES (?, ?)");
    pstmt.setLong(1, 1L);
    pstmt.setBytes(2, b);
    pstmt.execute();
    ...
}