簡體   English   中英

case = 1 時的條件計數,DB2

[英]Conditional count when case = 1, DB2

我目前正在嘗試找出在 Iseries 的 DB2 中將條件計數作為別名的最佳方法。 以下值表示可以創建、完成和取消作業的作業狀態,因此任何一項作業都可能附加多個狀態代碼。

但是,對於我的最終價值,我正在嘗試計算僅具有已創建狀態的工作,以便我可以顯示仍有多少工作處於開放狀態。 基本上尋找已創建案例的計數 = 1,但以下在“=”處失敗的案例

SELECT
  COUNT(CASE A1.JOB WHEN = 'CREATED' THEN 1 END) AS CREATED,
  COUNT(CASE A1.JOB WHEN = 'CANCELLED' THEN 1 END) AS CANCELLED,
  COUNT(CASE WHEN A1.JOB 'CREATED' = 1 then 1  END)  AS OPEN
FROM SCHEMA.TABLE A1;

樣本數據和結果:

    Job ID   |   Status_code
-------------------------
123         'CREATED'
123         'COMPLETED'
521         'CREATED'
521         'CANCELLED'
645         'CREATED'

結果:

JOB  |  CREATED  |   CANCELLED   |   OPEN
-------------------------------------------
123     1               0               0
521     1               1               0
645     1               0               1

假設唯一的“關閉”狀態是'CANCELLED' ,您可以像這樣使用not exists

select count(*)
from schema.table t
where t.status_code = 'CREATED' and
      not exists (select 1
                  from schema.table t2
                  where t2.job = t.job and
                        t2.status_code in ('CANCELLED', 'COMPLETED', 'DELETED')
                 );

如果您想要多個計數,那么像這樣的過濾不起作用。 所以先按工作匯總:

select sum(is_created) as num_created,
       sum(is_cancelled) as num_cancelled,
       sum(is_created * (1 - is_cancelled) * (1 - is_completed) * (1 - is_deleted)) as open
from (select job,
             max(case when status_code = 'CREATED' then 1 else 0 end) as is_created,
             max(case when status_code = 'CANCELLED' then 1 else 0 end) as is_cancelled,
             max(case when status_code = 'COMPLETED' then 1 else 0 end) as is_completed,
             max(case when status_code = 'DELETED' then 1 else 0 end) as is_deleted
      from t
      group by job
     ) j

使用條件聚合:

SELECT
  JobID,
  MAX(CASE Status_code WHEN 'CREATED' THEN 1 ELSE 0 END) AS CREATED,
  MAX(CASE Status_code WHEN 'CANCELLED' THEN 1 ELSE 0 END) AS CANCELLED,
  MIN(CASE WHEN Status_code <> 'CREATED' THEN 0 ELSE 1 END) AS OPEN
FROM tablename 
GROUP BY JobID 

請參閱演示
結果:

> JobID | CREATED | CANCELLED | OPEN
> ----: | ------: | --------: | ---:
>   123 |       1 |         0 |    0
>   521 |       1 |         1 |    0
>   645 |       1 |         0 |    1

以下返回您需要的結果:

WITH TAB (Job_ID, JOB) AS 
(
VALUES
  (123, 'CREATED')
, (123, 'COMPLETED')
, (521, 'CREATED')
, (521, 'CANCELLED')
, (645, 'CREATED')
)
SELECT
  Job_ID
, COUNT(CASE A1.JOB WHEN 'CREATED'   THEN 1 END) AS CREATED
, COUNT(CASE A1.JOB WHEN 'CANCELLED' THEN 1 END) AS CANCELLED
, CASE 
    WHEN NULLIF(COUNT(1), 0) = COUNT(CASE A1.JOB WHEN 'CREATED' then 1 END) 
    THEN 1 
    ELSE 0 
  END AS OPEN
FROM TAB A1
GROUP BY JOB_ID;

假設有效的關閉狀態是“COMPLETED”或“CANCELLED”,您可以嘗試關注 SQL。

SELECT
  A1.JobID,
  sum(CASE  WHEN A1.Status_code = 'CREATED' THEN 1 ELSE 0 END) AS CREATED,
  sum(CASE  WHEN  A1.Status_code = 'CANCELLED' THEN 1 ELSE 0 END) AS CANCELLED,
  (
     SUM(CASE WHEN A1.Status_code = 'CREATED' THEN 1 ELSE 0 END)
   - sum(CASE WHEN A1.Status_code = 'CANCELLED' THEN 1 ELSE 0 END)
   - sum(CASE WHEN A1.Status_code = 'COMPLETED' THEN 1 ELSE 0 END)
 ) AS OPEN
FROM SCHEMA.TABLE A1
GROUP BY A1.JobID 

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM