我無法讓 if 循環在 tkinter 代碼中工作

Question

最近我一直在嘗試在沒有pygame的情況下在 python 中構建一個游戲（我想要一個挑戰），但遇到了一個問題。 我不能在主循環中使用if循環。

這是我現在擁有的代碼，如果有人可以幫助我，我將不勝感激！

我試圖清除 canvas 然后在其中添加更多框，但if循環再次不起作用。 我也嘗試過while循環和for循環，但它們也不起作用。

import tkinter as tk
import time

dieplease= "dieplease"
play = False
accepted = ["admin1 LET ME IN"] #accepted names
count = len(accepted)
score = 0

windowEA= tk.Tk()

boxy = tk.Canvas(windowEA, width = 400, height = 300)
boxy.pack()     #canvas adjustments

label1 = tk.Label(windowEA, text="""You need Authorisation to get into this file so, please enter
your username and password to be allowed to play.""")
label1.config(font=('helvetica', 12))   #tkinter canvas config
boxy.create_window(200, 25, window=label1)

entry1 = tk.Entry (windowEA)    #creation of username entry box
boxy.create_window(200, 100, window=entry1)
entry2 = tk.Entry (windowEA)    #creation of password entry box
boxy.create_window(200, 120, window=entry2)
entry2.config(show="*")

x1 = entry1.get()
x2 = entry2.get()
namer = x1+" "+x2

def namecheck (): #checking if the name given fits with the allowed ones
    global play
    found = False
    x1 = entry1.get()
    x2 = entry2.get()
    namer = x1+" "+x2

    for d in range(count):
        if namer == accepted[d]:
            found = True
    if found == True:
        label1 = tk.Label(windowEA, text= "welcome to the game")
        boxy.create_window(200, 230, window=label1)
        output = "welcome to the game"
        play = True
    else:
        label1 = tk.Label(windowEA, text= "Sorry incorrect information")
        boxy.create_window(200, 230, window=label1)
        output = "Sorry incorrect information"

def quit():
    boxy.delete("all")

button1 = tk.Button(text="check", command=namecheck)
boxy.create_window(220, 180, window=button1)    #checking if info is good button
button2 = tk.Button(text="Login", command=quit)
boxy.create_window(180, 180, window=button2)    #login on button

if play == True:
    print("HI") #checking
    #this is where I want it to work
windowEA.mainloop()

Answer 1

利用 tkinter 中的 .after 方法來安排定期調用 function，比如每 100 毫秒。

在此 function 中，您可以執行更新游戲所需的任何邏輯/代碼。 這與 pygame 將有一個重新繪制/更新項目的 function 非常相似。

import tkinter as tk

def update():
    #Code here to perform your if and any other code
    print("Updating")
    root.after(100,update)

root = tk.Tk()

root.after(100,update)
root.mainloop()