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[英]How do I test with Postman a Controller's method which has one (or multiple) objects as parameters in a Spring Application?
[英]How to serialize an object which it's method has multiple parameters
我是 java 的初學者,我需要幫助。 我有兩個班級,一個(宋)看代碼是第二個(日期)的孩子。 Song 是可序列化的,而 Date 是不可序列化的(我打算以這種方式保留 Date class)。 我正在使用來自 Date 的方法,稱為 setDate,它需要三個參數,月、日和年,都是整數。 我正在嘗試使用自定義序列化(使用 readObject 和 writeObject 方法等)。
package assignment7;
import java.io.IOException;
import java.io.NotSerializableException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.io.Serializable;
/**
*
* @author Owner
*/
public class Song extends Date implements Serializable{
private String title;
private String artist;
private String genre;
//private String dateOpened;
//private Date obj = new Date();
public Song(){
}
public void setTitle(String t) {
title = t;
}
public void setArtist(String a) {
artist = a;
}
public void setGenre(String g) {
genre = g;
}
public void setDateOpen(int m, int d, int y){
setDate(m, d, y);
}
public void setDayOpen(){
}
public void setDayOpen(){
Date
}
public void setDayOpen(){
}
public String getDateOpen(){
return getDate();
}
public String getTitle() {
return title;
}
public String getArtist() {
return artist;
}
public String getGenre() {
return genre;
}
private void writeObject( ObjectOutputStream out ) throws IOException, ClassNotFoundException, NotSerializableException {
out.defaultWriteObject();
out.writeObject(getTitle());
out.writeObject(getArtist());
out.writeObject(getGenre());
out.writeObject(getDateOpen());
}
private void readObject( ObjectInputStream in ) throws IOException, NotSerializableException, ClassNotFoundException {
in.defaultReadObject();
setTitle((String)in.readObject());
setArtist((String)in.readObject());
setGenre((String)in.readObject());
setDateOpen((int)in.readObject(), (int)in.readObject(), (int)in.readObject());
}
}
問題是 getDateOpen 方法返回一個字符串,而 setDateOpen 需要 3 個整數。 有沒有辦法讓 readObjects() 讀取 3 個整數,而 output 仍然是一個序列化的字符串? (iv'e 還包括我的老師說不要更改的日期 class)
package assignment7;
import java.util.Scanner;
public class Date
{
private int month;
private int day;
private int year;
public Date() { month = 0; day = 0; year = 0; }
public Date( int m, int d, int y )
{
month = editMonth( m );
day = editDay( d );
year = editYear( y );
}
public void setDate( int m, int d, int y )
{
month = editMonth( m );
day = editDay( d );
year = editYear( y );
}
public String getDate( )
{
return month + "/" + day + "/" + year;
}
public int getMonth() { return month; }
public int getDay() { return day; }
public int getYear() { return year; }
protected int editMonth( int m )
{
if( m >= 1 && m <= 12 )
return m;
else
{
Scanner input = new Scanner( System.in );
while( !( m >= 1 && m <= 12 ) )
{
System.out.print( "Month must be 1-12 --- Please re-enter: " );
m = input.nextInt();
}
return m;
}
}
protected int editDay( int d )
{
int [] monthDays = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
if( d >= 1 && d <= monthDays[month - 1] )
return d;
else
{
Scanner input = new Scanner( System.in );
while( !( d >= 1 && d <= monthDays[month - 1] ) )
{
System.out.print( "Day must be 1 - " + monthDays[month - 1] + " ---
please re-enter: " );
d = input.nextInt();
}
return d;
}
}
protected int editYear( int y )
{
if( y >= 1 )
return y;
else
{
Scanner input = new Scanner(System.in);
while( y < 1 )
{
System.out.print( "Year must be greater than 1 --- please re-enter: "
);
y = input.nextInt();
}
return y;
}
}
}
如果Date
類型僅提供String
日期,那么您需要在某個時候傳遞它。 要么在writeObject
中解析並存儲int
,要么與String
保持串行形式並在readObject
中解析。
僅提供字符串化Date
的日期可能不是一個好的設計選擇。 也沒有辦法Song
應該是Date
的子類型(除非有一些關鍵的性能問題,這似乎不太可能)。
還要避免 Java 序列化。 JSON 似乎是通常的選擇。
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