[英]Parse JSONArray in Android Studio
我嘗試從 AndroidStudio 中的 PHP 腳本解析 JSONArray。 我從我的 PHP 腳本得到這個 JSON 響應: [{"0":"Firstname","meta_value":"Firstname"},{"0":"Lastname","meta_value":"Lastname"},{"valid":"1"},{"entered":"5"}]
現在我嘗試解析 JSONArray 以獲取值meta_value
,因此我想獲取 "Lastname" 和 "Firstname"。
但是我的代碼中一定有錯誤,因為我得到了響應: Exception: No value for meta_value
public class SendPostRequest extends AsyncTask<String, Void, String> {
String data ="";
String dataParsed = "";
String singleParsed ="";
protected void onPreExecute(){}
protected String doInBackground(String... arg0) {
try {
URL url = new URL("https://sample.com/code2.php"); // here is your URL path
JSONObject postDataParams = new JSONObject();
postDataParams.put("sdata", scannedData);
Log.e("params",postDataParams.toString());
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
BufferedReader in=new BufferedReader(new
InputStreamReader(
conn.getInputStream()));
StringBuffer sb = new StringBuffer("");
String line="";
while((line = in.readLine()) != null) {
data = data + line;
sb.append(line);
break;
}
in.close();
JSONArray reader2 = new JSONArray(data);
for(int i =0 ;i <reader2.length(); i++){
JSONObject JO = (JSONObject) reader2.get(i);
singleParsed = "Name:" + JO.get("meta_value") + "\n";
dataParsed = dataParsed + singleParsed +"\n" ;
}
return dataParsed;
}
else {
return new String("false : "+responseCode);
}
}
catch(Exception e){
return new String("Exception: " + e.getMessage());
}
}
@Override
protected void onPostExecute(String result) {
Toast.makeText(getApplicationContext(), result,
Toast.LENGTH_LONG).show();
}
}
請不要將我的答案標記為重復,因為我搜索了 2 周但沒有找到答案:謝謝:)
我建議您使用 GSON 序列化和反序列化您的 JSON 響應。 這使得它很容易處理。 GSON 。
樣本:
new Gson().fromJson("YourJsonHere",JsonElement.class);
干杯塔里克
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