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為什么在查詢時即使參數是String,String也會被轉換為Long

[英]Why String get converted to Long even when the parameter is String when querying

@Entity
@Getter
@Setter
@Table(name = "product_wallet")
@NamedQuery(name = "ProductWallet.findAll", query = "SELECT pw FROM ProductWallet pw")
@EntityListeners(CUEntityListener.class)
public class ProductWallet implements Serializable, CUEntity {

  private static final long serialVersionUID = 1L;
@Id
  @GeneratedValue(strategy = GenerationType.IDENTITY)
  @Column(name = "product_wallet_id", unique = true, nullable = false)
  private Long productWalletId;

  @Column
  private Integer total;

  @Column
  private String status;

  @Column(name = "user_id", updatable = false, insertable = false)
  private String userId;

  @Column(name = "member_id", updatable = false, insertable = false)
  private Long memberId;

  @Column(name = "provider_id", updatable = false, insertable = false)
  private String providerId;

  @Column(name = "created_by", length = 100)
  private String createdBy;

  @Column(name = "created_date")
  private Timestamp createdDate;

  @Column(name = "modified_by", length = 50)
  private String modifiedBy;

  @Column(name = "modified_date")
  private Timestamp modifiedDate;

  //bi-directional many-to-one association to MUser
  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumn(name = "user_id", referencedColumnName = "user_id")
  private MUser user;

  @OneToOne(fetch = FetchType.LAZY)
  @JoinColumn(name = "member_id")
  private Member member;

  @OneToOne(fetch = FetchType.LAZY)
  @JoinColumn(name = "provider_id")
  private Provider provider;

  @OneToMany(fetch = FetchType.LAZY, mappedBy = "productWallet")
  private List<ProductWalletItem> productWalletItems;

我正在嘗試使用 JPA 的自動查詢創建、手動編寫查詢等來使用此方法。

ProductWallet findProductWalletByProviderIdAndMemberId(String providerId, Long memberId);

但由於某種原因,所有字符串 providerId 都轉換為 Long ,我收到此錯誤。 似乎 jdbc 正在拼命嘗試將某些內容轉換為 Long:

Bad value for type long : PR_0000000288
2019-10-11 19:12:56 - Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute query; SQL [select productwal0_.product_wallet_id as product_1_41_, productwal0_.created_by as created_2_41_, productwal0_.created_date as created_3_41_, productwal0_.member_id as member_i4_41_, productwal0_.modified_by as modified5_41_, productwal0_.modified_date as modified6_41_, productwal0_.provider_id as provider7_41_, productwal0_.status as status8_41_, productwal0_.total as total9_41_, productwal0_.user_id as user_id10_41_ from product_wallet productwal0_ where productwal0_.provider_id=? and productwal0_.member_id=?]; nested exception is org.hibernate.exception.DataException: could not execute query] with root cause
org.postgresql.util.PSQLException: Bad value for type long : PR_0000000288
    at org.postgresql.jdbc.PgResultSet.toLong(PgResultSet.java:2860)
    at org.postgresql.jdbc.PgResultSet.getLong(PgResultSet.java:2114)
    at org.postgresql.jdbc.PgResultSet.getLong(PgResultSet.java:2506)
    at com.zaxxer.hikari.proxy.HikariResultSetProxy.getLong(HikariResultSetProxy.java)
    at org.hibernate.type.descriptor.sql.BigIntTypeDescriptor$2.doExtract(BigIntTypeDescriptor.java:63)
    at org.hibernate.type.descriptor.sql.BasicExtractor.extract(BasicExtractor.java:47)

我認為這是因為您的表中有兩個provider_id列。 一個用於歸檔的providerId ,另一個用於Provider object 的連接列。 我假設 object Provider的 id 是 Long 類型。 您可以重命名其中一個並嘗試嗎?

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