Flask BuildError - 無法為端點構建 URL

Question

我有一個非常簡單的 python 代碼到 select 我的數據庫中的一些數據

@app.route('/studentsearch', methods = ['POST', 'GET'])
def searchstudent():
    """ Displays the student search page for the site """
    cursor = mydb.cursor()
    cursor.execute ("SELECT * FROM student")
    all_students = cursor.fetchall()
    cursor.close()
    return render_template('studentsearch.html', all_students = all_students)

但是當我 go 渲染 HTML 頁面時，我得到werkzeug.routing.BuildError: Could not build url for endpoint 'studentsearch'。 你指的是“newstudent”嗎？

我的桌子也很直接......

<table>
    <thread>
        <tr>
            <th>Student ID:</th>
            <th>First Name:</th>
            <th>Last Name:</th>
            <th>Click to View Student Details</th>
        </tr>
    </thread>
    <tbody>
        {% for each_result in all_students %}
            <tr>
                <td>{{ each_result[0] }}</td>
                <td>{{ each_result[1] }}</td>
                <td>{{ each_result[2] }}</td>
                <td>CLICK HERE!!!</td>
            </tr>
        {% endfor %}
    </tbody>
</table>

這是怎么回事？ python 或 HTML 中甚至沒有提到“newstudent”？

根據要求，這里是“newstudent”似乎來自的代碼：

def newstudent():
    """Displays the new student page for the site"""
    return render_template('newstudent.html')

@app.route('/process_newstudent', methods = ['POST', 'GET'])
def process_newstudent():
    """ Processes the data from the new student course """
    if request.method == 'POST':
        first_name = request.form['firstname']
        last_name = request.form['lastname']
        year_began = request.form['yearbegan']

        try:
            cursor = mydb.cursor()
            cursor.execute ("INSERT INTO student (first_name, last_name, year_began) VALUES ('{}','{}','{}');".format((first_name.title()), (last_name.title()), year_began))
            mydb.commit()
            cursor.close()
        except mysql.connector.Error as err:
            cursor.close()
            return failure('newstudent', f"Error message: {err}. Student not added")
        else:
            cursor = mydb.cursor()
            cursor.execute ("SELECT * FROM student")
            student_success = cursor.fetchall()
            cursor.close()
            return render_template('newstudent_success.html', student_success = student_success)
    else:
        request.method == 'GET'
        return render_template('newstudent.html')

Answer 1

您是否嘗試使用url_for function 在應用程序代碼或 HTML 代碼的某處構建動態 URL？

如果是，那么我認為可能發生的情況是您將參數'studentsearch'傳遞給 function 而不是'searchstudent' （ url_for使用視圖 function 名稱構建端點，而不是端點名稱）。 例如，在 HTML 模板中，有問題的 URL 將像這樣構建：

<a href="{{ url_for('searchstudent') }}">Search</a>