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[英]Using a python for loop to print numbers from a list which are not in order of their index
[英]Python Loop to List Print Index or Array
下午好,Python 新手在這里。 我正在嘗試返回從文本文件中抓取的客戶信息列表。 我需要 output 采用名稱、帳號、日期格式。 我最初的想法是,
抓取數據創建列表按 index_number 打印,例如(姓名 1、帳號 1、日期 1)
不幸的是,這不起作用,因為列表將打印出所有名稱,然后是所有帳號,然后是日期。 我需要將列表打印為姓名、帳號、日期。
我很確定這是因為我運行循環的方式。 下面是我一直在處理的代碼。
import re
fin = open(destFileLoc,"r")
text = fin.read()
nameMatch = re.findall(r'\n\w+\s+\w+\s\w+', text)
# for i in range(len(nameMatch)):
# name = nameMatch # print("Name: " + nameMatch[i])
acctMatch = re.findall(r'\s{4}\d{8}', text)
# for i in range(len(acctMatch)):
# account = acctMatch ##print("Account Num: " + acctMatch[i])
dateMatch = re.findall(r'(\d+/\d+/\d+)', text)
# for i in range(len(dateMatch)):
# date = dateMatch ## print("Date of Service : " + dateMatch[i])
patList = [[nameMatch], [acctMatch], [dateMatch]]
for i in range(patList):
print("====== Name Account Number Date ======\n" + str(nameMatch[i]), str(acctMatch[i]), str(dateMatch[i]))
您可以嘗試使用結合了多個列表的 zip
for name, acctNum, date in zip(nameMatch, acctMatch, dateMatch):
print(str(name), str(acctNum), str(date))
嘗試...
另見format
模塊
nameMatch =["Smith", "Jones", "Thompson"]
acctMatch =["12345", "54321", "22333"]
dateMatch =["2019-10-1", "2019-10-2", "2019-10-3"]
a = list(zip(
nameMatch,
acctMatch,
dateMatch
))
print(a)
for _list in a:
print("=========================")
print("Printing the list itself: ", _list)
print ('Printing the items in _list:', _list[0], _list[1], _list[2])
print("=========================")
print ('Printing the items with format and columns:')
for _list in a:
print( '{0:.<10}{1:.<10}{2:.<10}'.format(_list[0], _list[1], _list[2]))
OUTPUT:
[('Smith', '12345', '2019-10-1'), ('Jones', '54321', '2019-10-2'), ('Thompson', '22333', '2019-10-3')]
=========================
Printing the list itself: ('Smith', '12345', '2019-10-1')
Printing the items in _list: Smith 12345 2019-10-1
=========================
Printing the list itself: ('Jones', '54321', '2019-10-2')
Printing the items in _list: Jones 54321 2019-10-2
=========================
Printing the list itself: ('Thompson', '22333', '2019-10-3')
Printing the items in _list: Thompson 22333 2019-10-3
=========================
Printing the items with format and columns:
Smith.....12345.....2019-10-1.
Jones.....54321.....2019-10-2.
Thompson..22333.....2019-10-3.
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