簡體   English   中英

如何從 firebase 分配增量 ID 號

[英]How to assign increment ID number from firebase

我是 Android Studio 的新手。 我想從“1”分配唯一的 id(增量),但是每當我注冊帳戶時,我總是只得到一個。

btn_register.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            final String email = et_email.getText().toString().trim();
            final String username = email.split("@")[0];
            final String pwd = et_password.getText().toString().trim();
            final long usr_id = 0; // not increment

            if (email.isEmpty() || pwd.isEmpty()) {
                et_email.setError("Entering Email Password Is required");
                et_email.requestFocus();
                return;
            }
            if (!Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
                et_email.setError("Entering Valid Email is required");
            }
            if (pwd.length() < 3) {
                et_password.setError("Password Length Should More Than 3");
                et_password.requestFocus();
            } else {
                m_auth.createUserWithEmailAndPassword(email, pwd).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {
                    DatabaseReference ref = FirebaseDatabase.getInstance().getReference().child("users");
                    DatabaseReference usr_uid = ref.child(m_auth.getCurrentUser().getUid());
                    if (task.isSuccessful()) {
                        Toast.makeText(MainActivity.this, "Registration Successed", Toast.LENGTH_SHORT).show();
                        //User usr = new User(email,username,usr_id+1);

                        usr_uid.child("email").setValue(email);
                        usr_uid.child("username").setValue(username);
                        usr_uid.child("password").setValue(pwd);
                        usr_uid.child("icon").setValue("default_icon");
                        usr_uid.child("id").setValue(String.valueOf(usr_id+1));

                        Intent refer_to_home = new Intent(MainActivity.this, Home_Activity.class);
                        startActivity(refer_to_home);
                        finish();
                    }
                    else
                        Log.e("user_reg_fail", "Field Empty!");
                    }
                });
            }
        }
    });

這是我的 model:

public class User {

    private String email;
    private String username;
    private long usr_id=0;
    private String icon;

    public User(String email, String username, long id) {
        this.email = username;
        this.username = username;
        this.usr_id = id;
    }

    public void setIcon(String icon) {
        this.icon = icon;
    }

    public User() {
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public long getId() {
        return usr_id;
    }

    public void setId(long id) {
        this.usr_id = id;
    }
}

我得到的數據庫

dldnPGvVsHeQmVqHkuJS4no4g1r1
|-email: "effeff@gmail.com"
|-icon: "default_icon"
|-id: "1"   //from one
|-password: "xxx"
|-username: "effeff"
gWEvZMOgi7hmuU5xOXhlG3vibgj1
|-email: "feefee@gmail.com"
|-icon: "default_icon"
|-id: "1" // id is still one
|-password: "xxx"
|-username: "feefee"

我不知道為什么它不增加 ID。 我怎樣才能獲得增量“2”“3”? 我可以成功注冊我的帳戶,但它只保留分配 ID“1”

所以在你的onClick方法里面你有這些行

final long usr_id = 0; // not increment
...
usr_uid.child("id").setValue(String.valueOf(usr_id+1));

每次單擊該按鈕時, usr_id都會將其值設置為 0。

使用 firebase 您有一個唯一的文檔 ID(您的問題中的示例是dldnPGvVsHeQmVqHkuJS4no4g1r1gWEvZMOgi7hmuU5xOXhlG3vibgj1 )您不需要任何額外的 id

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM