[英]How to round decimal values with bash script?
運行一些代碼后,我確實得到了這個 4D 數組,它保存在一個 txt 文件中,值很長,所以我需要將它們四舍五入到小數點后 6 位,更改應該在原始文件中完成,所以我可以數組的相同格式不只是打印值
這里是數組的一部分
[[[[-0.027340000495314598, -0.07065500319004059, 0.06236099824309349, -0.11684399843215942, -0.05784200131893158], [-0.16122999787330627, -0.14122700691223145, -0.1653739959001541, 0.1630070060491562, 0.05366099998354912], [0.035610001534223557, -0.05879399925470352, 0.06178700178861618, 0.15509599447250366, -0.11066299676895142], [-0.006271999794989824, -0.04911699891090393, -0.06760299950838089, -0.005801999941468239, 0.02808699943125248], [-0.1022690013051033, -0.08862099796533585, 0.14321200549602509, -0.00038400001358240843, 0.10744699835777283]]
$ echo '[[[[-0.027340000495314598, -0.07065500319004059, 0.06236099824309349' |
perl -pe 's/([-+]?[0-9]*\.[0-9]+|[0-9]+)/sprintf "%.6f","$1"/ge'
[[[[-0.027340, -0.070655, 0.062361
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