如何獲取具有多個鍵的對象數組中所有鍵的值，然后將它們全部相加[暫停]

Question

 var arrayOfObjects = [ { value1: 50, }, { value2: 100, value3: 600 }, { value4: 500, value5: 700 } ]; for (var i = 0; i < arrayOfObjects.length; i++) { var key = Object.values(arrayOfObjects[i]); var sum = 0; for (var j = 0; j < key.length; j++) { var key = Object.values(arrayOfObjects[j]); var string = key[j]; var sum = sum + (string); console.log(key); } }

Answer 1

您可以將flatMap與Object.values結合使用，以獲得所有值的扁平數組。 然后你可以將它們與reduce相加：

 var arrayOfObjects = [ { value1: 50, }, { value2: 100, value3: 600 }, { value4: 500, value5: 700 } ]; var total = arrayOfObjects.flatMap(Object.values).reduce((a, b) => a + b, 0); console.log(total);

Answer 2

使用減少

  var arrayOfObjects = [
  { value1: 50, },
  { value2: 100, value3: 600 },
  { value4: 500, value5: 700 }
];

const sum = arrayOfObjects.reduce((total, current) => {
    const values = Object.values(current);
    return values.length > 1 ? values.reduce((last, next) => last + next, 0) + total : total
}, 0)

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