Volley 庫在發布請求時給出錯誤 500

Question

我有以下代碼用於將數據保存到 mysql 數據庫中；

    private void save(final String orderId, final String client, final String name, final String Seller, final String amount, final String quantity, final double longi, final double lat, final String location, final ProgressDialog progressDialog) {
    String URL_ORDER = "https://foodfuzz.co.ke/foodfuzzbackend/market/orders/order.php";
    StringRequest orderStringRequest = new StringRequest(Request.Method.POST, URL_ORDER,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        JSONObject orderObject = new JSONObject(response);
                        String orderSuccess = orderObject.getString("success");
                        if(orderSuccess.equals("1")){
                            Toast.makeText(CheckOutActivity.this,"Order Placed Successfully " , Toast.LENGTH_SHORT).show();
                            pay.setVisibility(View.GONE);
                        }
                    } catch (JSONException e) {
                        e.printStackTrace();
                        progressDialog.dismiss();
                        Toast.makeText(CheckOutActivity.this,"Unable to place order " + e.toString(), Toast.LENGTH_SHORT).show();
                        pay.setEnabled(true);
                    }
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    progressDialog.dismiss();
                    Toast.makeText(CheckOutActivity.this,"Error placing order " + error.toString(), Toast.LENGTH_SHORT).show();
                    pay.setEnabled(true);
                }
            }){
        protected Map<String, String> getParams() {
            Map<String, String> params = new HashMap<String, String>();
            params.put("orderId",orderId);
            params.put("name", name);
            params.put("client", client);
            params.put("seller", Seller);
            params.put("amount", amount);
            params.put("quantity",quantity);
            params.put("longitude",String.valueOf(longi));
            params.put("latitude",String.valueOf(lat));
            params.put("location",location);
            return params;
        }
    };
    RequestQueue orderRequestQueue = Volley.newRequestQueue(this);
    orderRequestQueue.add(orderStringRequest);

}

我的問題是當我發出發布請求時收到錯誤代碼 500。 以下是logcat上記錄的實際錯誤

BasicNetwork.performRequest: Unexpected response code 500 for https://foodfuzz.co.ke/foodfuzzbackend/market/orders/order.php

這是 url 服務器上的 php 代碼

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    require_once '../db/connector.php';
    $orderId = mysqli_real_escape_string($conn, $_POST['orderId']);
    $client = mysqli_real_escape_string($conn, $_POST['client']);
    $product = mysqli_real_escape_string($conn, $_POST['name']);
    $seller = mysqli_real_escape_string($conn, $_POST['seller']);
    $amount = mysqli_real_escape_string($conn, $_POST['amount']);
    $quantity = mysqli_real_escape_string($conn, $_POST['quantity']);
    $longi = mysqli_real_escape_string($conn, $_POST['longitude']);
    $lati = mysqli_real_escape_string($conn, $_POST['latitude']);
    $loc = mysqli_real_escape_string($conn, $_post['location']);
    $status = 1;

    $sql = "INSERT INTO tbl_orders (orderid, client, product, seller, amount, quantity, longitude, latitude, deliveryloc, status) VALUES ('$orderId', '$client', '$product', '$seller', '$amount', '$quantity', '$longi', '$lati', '$loc', '$status')";

    if (mysqli_query($conn, $sql)) {
        $result["success"] = "1";
        $result["message"] = "success";

        echo json_encode($result);
        mysqli_close($conn);
    } else {

        $result["success"] = "0";
        $result["message"] = "error";

        echo json_encode($result);
        mysqli_close($conn);
    }
}

該代碼適用於 postman 沒有任何錯誤。 我可能做錯了什么

Answer 1

此錯誤通常是由您的代碼中的錯誤引起的，首先最好檢查您的 php 腳本是否無錯誤以及其他代碼是否正確。 在我的情況下，發布數據與表格列不匹配。