[英]INSERT into statement not working in oracle when using INSERT INTO .. SELECT * FROM
我有vh_emp
表,其表結構為(這是空表):
我正在從employee
表中獲取數據作為源表,我在其中編寫了一些查詢以匹配 vh_emp 表:
SELECT e.emp_id EMP_ID,
e.emp_name EMP_NAME,
e.dob DOB,
e.join_date JOIN_DATE,
CASE
WHEN e.leave_date IS NULL THEN Trunc(sysdate)
ELSE e.leave_date
END AS LEAVE_DATE,
e.salary / 100 SALARY,
d.dept_name DEPT_NAME,
one.addr_name ADDRESS_ONE,
two.addr_name ADDRESS_TWO,
b.emp_name AS MANAGER_NAME
FROM offc.employee e
LEFT JOIN offc.department d
ON e.dept_id = d.dept_id
LEFT JOIN offc.add_line_one one
ON e.line1 = one.addr_id_one
LEFT JOIN offc.add_line_two two
ON e.line2 = two.addr_id_two
LEFT OUTER JOIN (SELECT *
FROM offc.employee) b
ON e.manager_id = b.emp_id;
查詢運行良好,並且 output 從此查詢運行良好:
所以,我想使用以下方法將這些數據插入vh_emp
表中:
INSERT INTO offc.vh_emp
(emp_id,
emp_name,
dob,
join_date,
leave_date,
address_one,
address_two,
salary,
manager_name,
dept_name)
SELECT e.emp_id EMP_ID,
e.emp_name EMP_NAME,
e.dob DOB,
e.join_date JOIN_DATE,
CASE
WHEN e.leave_date IS NULL THEN Trunc(sysdate)
ELSE e.leave_date
END AS LEAVE_DATE,
e.salary / 100 SALARY,
d.dept_name DEPT_NAME,
one.addr_name ADDRESS_ONE,
two.addr_name ADDRESS_TWO,
b.emp_name AS MANAGER_NAME
FROM offc.employee e
LEFT JOIN offc.department d
ON e.dept_id = d.dept_id
LEFT JOIN offc.add_line_one one
ON e.line1 = one.addr_id_one
LEFT JOIN offc.add_line_two two
ON e.line2 = two.addr_id_two
LEFT OUTER JOIN (SELECT *
FROM offc.employee) b
ON e.manager_id = b.emp_id;
但是,我執行了這個查詢我得到了錯誤:
ORA-01722: invalid number
為什么會出現這個錯誤? 我查看並看到 select 語句的列和值的數據類型相同。由於列數據類型匹配,因此不應出現此錯誤。
您的insert
子句列名和select
子句列名的順序應該匹配。
請將它們的位置匹配如下:
INSERT INTO offc.vh_emp
(emp_id,
emp_name,
dob,
join_date,
leave_date,
Salary, -- this
dept_name, -- this
address_one,
address_two,
manager_name
)
SELECT e.emp_id EMP_ID,
e.emp_name EMP_NAME,
e.dob DOB,
e.join_date JOIN_DATE,
CASE
WHEN e.leave_date IS NULL THEN Trunc(sysdate)
ELSE e.leave_date
END AS LEAVE_DATE,
e.salary / 100 SALARY,
d.dept_name DEPT_NAME,
one.addr_name ADDRESS_ONE,
two.addr_name ADDRESS_TWO,
b.emp_name AS MANAGER_NAME
FROM offc.employee e
LEFT JOIN offc.department d
ON e.dept_id = d.dept_id
LEFT JOIN offc.add_line_one one
ON e.line1 = one.addr_id_one
LEFT JOIN offc.add_line_two two
ON e.line2 = two.addr_id_two
LEFT OUTER JOIN (SELECT *
FROM offc.employee) b
ON e.manager_id = b.emp_id;
干杯!!
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