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[英]C switch case values cannot be modified within the switch (not constant)
[英]Detecting Enter within a switch case in C?
在這方面遇到的麻煩比我應該的要多。 我正在構建一個非常簡單的銀行菜單界面,用戶可以在其中查看余額、存款、取款或退出菜單。 case 1
, case2
和case3
似乎工作正常,但case 4
不正確 function ,無論我嘗試什么谷歌。
在這個當前版本中,出現第case 4
種情況下的printf()
語句,然后似乎什么都沒有發生,直到我輸入其他選項之一 (1 - 3) 兩次,此時循環將循環並自動使用第二個選項輸入是。 我嘗試了getchar()
但這似乎不起作用(或者我沒有正確實現它)。
為什么會發生這種行為,我該如何解決?
這是代碼:
#include <stdio.h>
#include <cs50.h>
double deposit(double a, double b);
double withdraw(double a, double b);
int main(void)
{
int resume = 1;
int user_input = 0;
double user_balance = 10.00;
printf("Welcome to UBank!\n");
while (resume)
{
printf("\n====================\n");
printf("Select an operation:\n\n1. Show Balance\n2. Make a Deposit\n3. Make a Withdrawal\n4. Quit\n"
"====================\n\n");
scanf("%d", &user_input);
int quit_character = 0x00;
double deposit_amount = 0.00;
double withdraw_amount = 0.00;
switch (user_input)
{
case 1:
printf("Balance: $%.2lf\n", user_balance);
break;
case 2:
printf("How much would you like to deposit?\n");
scanf("%lf", &deposit_amount);
user_balance = deposit(user_balance, deposit_amount);
break;
case 3:
printf("How much would you like to withdraw?\n");
scanf("%lf", &withdraw_amount);
user_balance = withdraw(user_balance, withdraw_amount);
break;
case 4:
printf("Press Enter to finish banking or any other key to continue.\n");
scanf("%d\n", &quit_character);
if (quit_character == 0x0A)
{
resume = 0;
}
break;
}
}
}
double deposit(double a, double b)
{
if (b > 0 && b < 10000)
{
return a + b;
}
else
{
printf("Please enter a valid amount. (0.01 - 9999.99)\n");
return a;
}
}
double withdraw(double a, double b)
{
if (b > 0 && a - b >= 10)
{
return a - b;
}
else if (b <= 0)
{
printf("Withdrawal amount must be greater than $0.00.\n");
}
else if (a - b < 10)
{
printf("Withdrawal amount invalid. Remaining balance must be $10.00 or more.\n");
}
return a;
}
假設我想畫我家的外部。 我買了油漆,然后回到我家(從最近的商店開車 5 小時)。 當我回到家時,我意識到我忘了買一個畫筆。 我不想在接下來的 10 個小時里開車去拿油漆刷,但我應該怎么塗油漆呢?
我可以使用掃帚、拖把、抹布、我的手、我兒子的手等等,沒有一個比刷子更可取。 但后來我意識到……我有一匹馬,我剪下馬的主干並制作自己的畫筆。 我畫了一天。 下周當我需要另一把刷子時,再給我的馬夾一下。 這最終比 10 小時的車程便宜得多。
好吧……那是個老生常談的虛構故事。 關鍵是使用scanf()進行用戶輸入就像用豬鼻子畫畫。 這只是工作的錯誤工具。 最好按照您期望的方式編寫您自己的用戶輸入 function。
考慮下面的GetInput() function。 我必須自己做,但它肯定優於使用scanf()進行用戶輸入:
#include <stdio.h>
#include <stdlib.h>
double deposit(double a, double b);
double withdraw(double a, double b);
/*-----------------------------------------------------------------------------------
** Get input from user, and return it as specific types.
**
** Caller may specify NULL for any (or all) input types that are not needed.
*/
void GetInput(int *intOut, char *charOut, double *doubleOut)
{
// Pointer to a temporary (allocated memory) buffer to hold user input.
char *line_A = NULL;
// Number of bytes allocated to the temporary (allocated) buffer.
size_t lineSize = 0;
// Holds the number of bytes entered by the user, or (-1) for error.
ssize_t lineLength;
lineLength=getline(&line_A, &lineSize, stdin);
if(-1 == lineLength)
{
fprintf(stderr, "getline() failed.\n"
goto CLEANUP;
}
// If the caller did not specify NULL for intOut, ...
if(intOut)
// Convert the string to an int and pass it back to the caller.
*intOut = atoi(line_A);
if(charOut)
*charOut = *line_A;
if(doubleOut)
*doubleOut = atof(line_A);
CLEANUP:
if(line_A)
free(line_A);
return;
}
int main(void)
{
int resume = 1;
int user_input = 0;
double user_balance = 10.00;
printf("Welcome to UBank!\n");
while (resume)
{
printf("\n====================\n");
printf("Select an operation:\n\n1. Show Balance\n2. Make a Deposit\n3. Make a Withdrawal\n4. Quit\n"
"====================\n\n");
GetInput(&user_input, NULL, NULL); // Get an integer from the user.
char quit_character = 0x00;
double deposit_amount = 0.00;
double withdraw_amount = 0.00;
switch (user_input)
{
case 1:
printf("Balance: $%.2lf\n", user_balance);
break;
case 2:
printf("How much would you like to deposit?\n");
GetInput(NULL, NULL, &deposit_amount); // Get a double from the user.
user_balance = deposit(user_balance, deposit_amount);
break;
case 3:
printf("How much would you like to withdraw?\n");
GetInput(NULL, NULL, &withdraw_amount); // Get a double from the user.
user_balance = withdraw(user_balance, withdraw_amount);
break;
case 4:
printf("Press Enter to finish banking or any other key to continue.\n");
GetInput(NULL, &quit_character, NULL); //Get a character from the user.
if (quit_character == 0x0A)
{
resume = 0;
}
break;
}
}
}
double deposit(double a, double b)
{
if (b > 0 && b < 10000)
{
return a + b;
}
else
{
printf("Please enter a valid amount. (0.01 - 9999.99)\n");
return a;
}
}
double withdraw(double a, double b)
{
if (b > 0 && a - b >= 10)
{
return a - b;
}
else if (b <= 0)
{
printf("Withdrawal amount must be greater than $0.00.\n");
}
else if (a - b < 10)
{
printf("Withdrawal amount invalid. Remaining balance must be $10.00 or more.\n");
}
return a;
}
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