如何匹配一行中第一個字符后的字符串

Question

找到第一個匹配的字符串

s = '''
Name Mak How are you Name non Name anonymouse
Name Mak1 How are you Name non1
Name Mak2 How are you Name non2
'''

如何提取名字

My Expected Out
['Mak', 'Mak1', 'Mak2']

偽代碼

import re
re.findall(r'?Name (([\w]+)',s)

Answer 1

這是使用str.split的一種方法。

前任：

s = '''
Name Mak How are you Name non Name anonymouse
Name Mak1 How are you Name non1
Name Mak2 How are you Name non2
'''

print([line.split()[1] for line in s.splitlines() if line.startswith('Name')])

Output：

['Mak', 'Mak1', 'Mak2']

Answer 2

您可以使用：

>>> s = '''
... Name Mak How are you Name non Name anonymouse
... Name Mak1 How are you Name non1
... Name Mak2 How are you Name non2
... '''
>>> re.findall(r'(?m)^Name (\w+)', s)
['Mak', 'Mak1', 'Mak2']

正則表達式詳細信息：

• (?m)啟用多行模式
• ^ : 開始
• Name ：匹配文字文本，后跟一個空格
• (\w+) ：匹配 1+ 個單詞字符並在組 #1 中捕獲

Answer 3

re.findall(r'Name\s+([^\s]+).+', m)

細節

# Name - matches Name literally

# \s+ - matches one or more of white spaces

# ([^\s]+) - match one or more characters other from whitespace \s and store it inside first capturing group

# .+ - match one or more of any characters (except newline)