如何將每一行數據組合在一起？

Question

在 PHP 中，我想將每一行加在一起。
這是我自己的數據庫的總結示例：

c(CorporateID,CompanyName)
o(CorporateID,OutletID)
os(OutletID,StaffName)

數據：

c 表：

CorporateID   CompanyName
-----------   -----------
1             A&B Company

表：

CorporateID   OutletID
-----------   --------
1             1
1             2
1             3

操作系統表：

OutletID   StaffName
--------   ---------
1          Jeannie
1          Zoey
1          Jasmine
2          James
2          Catherine
3          Ada

PHP的一部分

$conn = new mysqli(server, dbuser, dbpw, db);
$query = "
    SELECT o.*, c.*, os.* 
    FROM Outlet o, Company c, OutletStaff os
    WHERE c.CorporateID = o.CorporateID
    AND o.OutletID = os.Outlet_ID";
$result = $conn->query($query);

$outp = "[";
while($rs = $result->fetch_array(MYSQLI_ASSOC)) {
    if ($outp != "[") {$outp .= ",";}
    $outp .= '{"CompanyName":"'. $rs["CompanyName"].' - Outlet'. $rs["OutletID"].'",';
    $outp .= '"Worker":"'.$rs["StaffName"].'"}';
}
$outp .="]";

$conn->close();

echo($outp);

Output

[{"CompanyName":"A&B - Outlet1","Worker":"Jeannie"},
{"CompanyName":"A&B - Outlet1","Worker":"Zoey"},
{"CompanyName":"A&B - Outlet1","Worker":"Jasmine"},
{"CompanyName":"A&B - Outlet2","Worker":"James"},
{"CompanyName":"A&B - Outlet2","Worker":"Catherine"},
{"CompanyName":"A&B - Outlet3","Worker":"Ada"}]

如您所見，由於該商店的工人不同，因此出現了重復的companyname 。

這是我的期望：

[{"CompanyName":"A&B - Outlet1","Worker":"Jeannie, Zoey, Jasmine"},
{"CompanyName":"A&B - Outlet2","Worker":"James, Catherine"},
{"CompanyName":"A&B - Outlet3","Worker":"Ada"}]

它能夠做到嗎？ 個人感覺跟PHP的第13行有關系：

$outp .= '"Worker":"'.$rs["StaffName"].'"}';

也許我需要循環然后放入一個變量，然后放入這個output？
我怎樣才能實現它？

Answer 1

假設您的 MySQL 響應如下所示；

$result = [
    [
        "company_name" => "ABC",
        "worker" => "Dipesh"
    ],
    [
        "company_name" => "CDE",
        "worker" => "Ramesh"
    ],
    [
        "company_name" => "CDE",
        "worker" => "Mukhesh"
    ]
];

您可以簡單地使用您的唯一鍵創建一個關聯數組，如下面的代碼片段所示。

$res = [];
foreach($result as $value){
 $company_name = $value['company_name'];
 if( isset($res[$company_name]) ){
    $res[$company_name] = array_merge($res[$company_name], [$value['worker']]);
 }else{
     $res[$company_name] = [$value['worker']]; 
 }
}

然后結合鍵和值使用 php implode function 輕松獲得所需的響應。

$result = [];
foreach($res as $key => $val){
   $result[] = [
     'company_name' => $key,
     'worker' => implode($val,",")
   ];   
}

對於JSON響應，您只需調用json_encode($result)即可獲得所需的 output。

[
  {
    "company_name": "ABC",
    "worker": "Dipesh"
  },
  {
    "company_name": "CDE",
    "worker": "Ramesh,Mukhesh"
  }
]